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3 years ago

Factor out the greatest common factor -5x^2 - 5x^3 - 15x^4

1 answer:

5 0

Our answer is $-5x^{2} (3x^{2} +x+1)$

Our greatest common factor, or GCF, is $-5x^{2}$ , so when we factor is out, our divide each term by $-5x^{2}$ , we get our answer. To check this, we can multiply the $-5x^{2}$ back across the parenthesis and see if we get the same result as our initial question.

Hope this helped! :))

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De acuerdo con la tercera ley de movimiento planetario de Kepler, la masa de un planeta es directamente proporcional al cubo de

Sunny_sXe [5.5K]

Answer:

La masa del Sol es $2.509\times 10^{31}$ kilogramos.

Step-by-step explanation:

Tras una lectura cuidadosa al enunciado, tenemos que la Tercera Ley de Kepler queda descrita por la siguiente relación:

$M \propto \frac{r^{3}}{T^{2}}$

$M = k\cdot \frac{r^{3}}{T^{2}}$ (Eq. 1)

Donde:

$r$ - Distancia entre los centros del planeta y el satélite, medido en kilómetros.

$T$ - Período oribital del satélite, medido en días.

$k$ - Constante de proporcionalidad, medida en kilogramo-días cuadrados por kilómetro cúbico.

$M$ - Masa del planeta, medida en kilogramos.

Podemos obtener la masa del Sol mediante la siguiente relación:

$\frac{M_{S}}{M_{E}} = \frac{\frac{r_{E}^{3}}{T_{E}^{2}} }{\frac{r_{M}^{3}}{T_{M}^{2}} }$

$\frac{M_{S}}{M_{E}} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3}$ (Eq. 2)

Donde:

$T_{M}$ , $T_{E}$ - Períodos orbitales de la Luna y la Tierra, medidos en días.

$r_{E}$ , $r_{M}$ - Distancias entre la Tierra y el Sol, así como entre la Luna y la Tierra, medidas en kilómetros.

$M_{S}$ , $M_{E}$ - Masas del Sol y la Tierra, medidos en kilogramos.

Si $M_{E} = 75.97\times 10^{24}\,kg$ , $T_{E} = 365.3\,d$ , $T_{M} = 27.3\,d$ , $r_{M} = 3.84\times 10^{5}\,km$ y $r_{E} = 1.496\times 10^{8}\,km$ , entonces tenemos que la masa del Sol es:

$M_{S} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3}\cdot M_{E}$

$M_{S} = \left(\frac{27.3\,d}{365.3\,d} \right)^{2}\cdot \left(\frac{1.496\times 10^{8}\,km}{3.84\times 10^{5}\,km} \right)^{3}\cdot (75.97\times 10^{24}\,kg)$

$M_{S} = 2.509\times 10^{31}\,kg$

La masa del Sol es $2.509\times 10^{31}$ kilogramos.

7 0

3 years ago

This is number three Nd I neeed help with this I can help you with anything

KATRIN_1 [288]

Answer:

a. False

b. False

c. True

d. True

e. True

5 0

3 years ago

The owner of a hot dog stand receives a loan of $3,750 at 8.25% for 9 months. find the amount of simple interest.(round to the n

Mkey [24]

Hello! The formula for simple interest is prt. That means you multiply the principal (initial amount) by the rate (simple interest percentage), by the amount of time (could be in months or years). So, the loan is $3,750 and the rate is 8.25% for 9 months. 9 months is 3/4 of the year, because there are 12 months in 1 year and 9/12 is 0.75. Let's multiply. 3,750 * 8.25% (0.0825) is 309.375 Now, multiply that number by 0.75 to get 232.03125 or 232.03 when rounded to the nearest hundredth (cent). The amount of simple interest is $232.03.

7 0

3 years ago

Solve the equation √x+9 - 9 = -4 show each step of your solution process

Serjik [45]

Answer:

Step-by-step explanation:

Start by adding 9 to both sides, obtaining: √(x + 9) = 5.

Square both sides, obtaining: x + 9 = 25.

Subtract 9 from both sides: x = 16

Note that √(16+9) - 9 = -4, as required.

3 0

3 years ago

I need help ASAP. The assignment is due at 11:59

Oksanka [162]

Answer:

its answer is 75 i guess

5 0

3 years ago

Read 2 more answers