Answer:
Density = 4.06 * 10^14
Explanation:
Givens
r = 1 * 10^-13 cm
m = 1.7 * 10^-24 grams
Formula
V = 4/3 * pi * r^3
D = m/V
Solution
Put the givens into the formula.
V = (4/3) 3.14 * (1 * 10^-13)^3 Find the value for r^3
V = (4/3) 3.14 * 1 * 10^-39 Find the volume. Indicate divide by 3
V = 1.256 10^-38/3
V = 4.1867 * 10^-39
Density = m / v
Density = 1.7*10^-24/4.1867*10^-39 Do the division
Density = .406 * 10^(-24 + 39)
Density = .406 * 10^15 grams/ cm^3
Answer: Density = 4.06 * 10^14
Answer:
Bohr o saka mi ad ha piebald webs ldb
Explanation:
Answer:
<h2>The answer is 70 kPa</h2>
Explanation:
In order to find the pressure if the volume were increased to 375 ml we use Boyle's law
That's
where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
Since we are finding the final pressure
From the question
P1 = 105 kPa = 105 , 000 Pa
V1 = 250 mL
V2 = 375 mL
So we have
We have the final answer as
<h3>70 kPa</h3>
Hope this helps you
Answer : The molality of NaCl is, 1.95 mol/kg
Explanation :
Formula used for Elevation in boiling point :
where,
= change in boiling point = 
= boiling point constant for water = 
m = molality
i = Van't Hoff factor = 2 (for electrolyte)
The dissociation 
will be,
So, Van't Hoff factor = Number of solute particles = 
= 1 + 1 = 2
Now put all the given values in the above formula, we get:
Therefore, the molality of NaCl is, 1.95 mol/kg
Answer:
0.667 L
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 250 mL
Initial concentration (C₁) = 12 M
Final concentration (C₂) = 4.5 M
Final volume (V₂) =?
The final volume of the solution can be obtained by using the dilution formula as illustrated below:
C₁V₁ = C₂V₂
12 × 250 = 4.5 × V₂
3000 = 4.5 × V₂
Divide both side by 4.5
V₂ = 3000 / 4.5
V₂ = 667 mL
Finally, we shall convert 667 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
667 mL = 667 mL × 1 L / 1000 mL
667 mL = 0.667 L
Thus, the volume of the solution prepared is 0.667 L
