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Softa [21]
3 years ago
8

Balance the following equation. Then determine the ratio for the products KCl and O2 generated during the decomposition of potas

sium chlorate. KClO3 KCl + O2 1:1 2:2 4:3 2:3 3:2
Chemistry
2 answers:
Alja [10]3 years ago
7 0

Answer: 2:3

Explanation: Decomposition reaction is a type of chemical reaction in which one reactant gives two or more than two products.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

2KClO_3\rightarrow 2KCl+3O_2

according to the balanced chemical equation, 2 moles of potassium chlortae on decomposition gives 2 moles of KCl and 3 moles of O_2.

drek231 [11]3 years ago
6 0
The answer is 2:3 for plato users

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Answer:

6 oxygen atoms

Explanation:

From the equation,

2Fe(OH)₃ → Fe₂O₃ + 3H₂O

From the reactant (left hand side) we have 2 moles of Fe(OH)₃ having (2 * 3 = 6) atoms of oxygen and decomposed to give Fe₂O₃ which contains 3 atoms of oxygen and 3 moles of water that also contains 3 atoms of oxygen.

Since the number of oxygen participating in the reaction is independent on the product (not a reversible reaction) then the total number of oxygen atoms participating in the reaction is 6

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One liter doesn't belong
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5 0
3 years ago
Decide whether the compound is ionic or molecular, if you can.
mestny [16]

Answer:

Molecular solid

Explanation:

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7 0
3 years ago
What is the pH of a KOH solution that has [H ] = 1. 87 × 10–13 M? What is the pOH of a KOH solution that has [OH− ] = 5. 81 × 10
vlada-n [284]

pH is the hydrogen ion concentration and pOH is the hydroxide ion concentration in the solution. pH KOH is 12.73, pOH KOH is 2.24 and pH NaCl is 7.

<h3>What are pH and pOH?</h3>

pH is the negative log of the hydrogen ion concentration and pOH is the negative log of the hydroxide ion concentration.

The relation between the pH and pOH can be given as, \rm pOH = 14 - pH

The pH of KOH can be calculated by the formula,

\rm pH = \rm -log [H^{+}]

In the first case, the concentration of the KOH is 1. 87 \times  10^{-13}\;\rm  M

Substituting values in the equation:

\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 87 \times  10^{-13}\;\rm  M ]\\\\&= 12.73\end{aligned}

Hence, the pH of KOH is 12.73.

<u />

pOH of KOH can be calculated by the formula,

\rm pOH = \rm -log [OH^{-}]

The hydroxide concentration of the KOH solution is 5. 81 \times 10^{-3}\;\rm  M

Substituting value in the equation:

\begin{aligned} \rm pOH &= \rm -log [OH^{-}]\\\\&= \rm -log [5. 81 \times 10^{-3}\;\rm  M ]\\\\&= 2.24 \end{aligned}

Hence, the pOH of KOH is 2.24

<u />

The pH of NaCl can be calculated by the formula,

\rm pH = \rm -log [H^{+}]

In the third case, the concentration of the NaCl is 1. 00\times 10^{-7}\;\rm  M

Substituting values in the equation:

\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 00 \times  10^{-7}\;\rm  M ]\\\\&= 7 \end{aligned}

Hence, the pH of KOH is 7.0.

Therefore, KOH is basic and NaCl is approximately neutral.

Learn more about pH and pOH here:

brainly.com/question/13885794

3 0
3 years ago
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