WILL ANYONE HELP ME?

The average lifetime of a poodle dog is 13.0 years. How fast is it traveling, u, relative to an observer who measures the averag

bogdanovich [222]

Answer:

The speed is 0.97 c.

Explanation:

Given that,

Dilated time t'= 50.0 years

Rest time t = 13.0 years

We need to calculate the speed

Using formula of time dilation

$t'=\dfrac{t}{\sqrt{1-\dfrac{v^2}{c^2}}}$

Where, t' = change in time

t = rest time

v = velocity

c = speed of light

Put the value into the formula

$50.0=\dfrac{13.0}{\sqrt{1-\dfrac{v^2}{(3\times10^{8})^2}}}$

$v^2=\dfrac{(13)^2\times(c)^2-(c)^2\times50^2}{50^2}$

$v^2= 0.9324c^2$

$v=0.97c$

Hence, The speed is 0.97 c.

6 0

3 years ago

While practicing S-turns, a consistently smaller half-circle is made on one side of the road than on the other, and this turn is

erica [24]

Answer:

The answer is "4-5-6 because the bank is growing too quickly in the beginning of its turn".

Explanation:

The S-turns is also known as the reference technique, in which the ground track of the aircraft on both sides of a defined ground-based straight-line distance represents 2 different but equivalent circles.

Throughout the S-turns, on either side of the road, a progressively smaller half-circle is formed, and this turn does not stop until the road or reference line is crossed during the early part of the turn, the twists increase too quickly.

5 0

3 years ago

A uniform solid disk and a uniform ring are place side by side at the top of a rough incline of height h.

nadezda [96]

Explanation:

velocity of disc $=\sqrt((gh)/0.75)$

lets call (h) 1 m to make it simple.

= 3.614 m/s

$\sqrt((4/3) x 1 x 9.8) = 3.614$ m/s pointing towards this:

$4×V_d=\sqrt(4/3hg)$

$V_h=\sqrt(hg)$

velocity of hoop= $\sqrt(gh)$

lets call (h) 1m to make it simple again.

$\sqrt(9.8 x 1) = 3.13$ m/s

$\sqrt(gh) = sqrt(hg)so [tex]4×V_d= \sqrt(4/3hg)V_h=\sqrt(hg)$

The disc is the fastest.

While i'm on this subject i'll show you this:

Solid ball $=0.7v^2= gh$

solid disc $= 0.75v^2 = gh$

hoop $=v^2=gh$

The above is simplified from linear KE + rotational KE, the radius or mass makes no difference to the above formula.

The solid ball will be the faster of the 3, like above i'll show you.

solid ball: velocity $=\sqrt((gh)/0.7)$

let (h) be 1m again to compare.

$\sqrt((9.8 x 1)/0.7) = 3.741$ m/s

solid disk speed $=\sqrt((gh)/0.75)$

uniform hoop speed $=\sqrt(gh)$

solid sphere speed $=\sqrt((gh)/0.7)$

8 0

3 years ago

A ball with a mass of 275 g is dropped from rest, hits the floor, and re-bounds upward. If the ball hits the floor with a speed

disa [49]

Answer:

a) $\Delta p = 1.350\,\frac{kg\cdot m}{s}$ , b) $\Delta p' = -0.454\,\frac{kg\cdot m}{s}$ , c) D. The magnitud of the change in the ball's momentum.

Explanation:

a) The magnitude of the change in the ball's momentum is:

$\Delta p = (0.275\,kg)\cdot \left[\left(1.63\,\frac{m}{s} \right)-\left(-3.28\,\frac{m}{s} \right)\right]$

$\Delta p = 1.350\,\frac{kg\cdot m}{s}$

b) The change in the magnitude of the ball's momentum:

$\Delta p' = (0.275\,kg)\cdot \left[(1.63\,\frac{m}{s} )-(3.28\,\frac{m}{s} ) \right]$

$\Delta p' = -0.454\,\frac{kg\cdot m}{s}$

c) The magnitude of the change in the ball's momentum is more directly related to the net force acting on the ball, as it measures the effect of the force on change in ball's motion at measured time according to the Impact Theorem. So, the right answer is option D.

3 0

4 years ago

Set up the Applied Force (force exerted) on both crates with the current Friction setting at 350 N. On Part 2, draw a force diag

ryzh [129]

The acceleration will be constantly equal to 1 m/s².Option c is correct.

<h3>What is force?</h3>

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

Given data;

Force,F = 350 N

Friction force,f=350 N

F=f

Because the frictional and applied forces on the two boxes are of equal strength, both move at the same pace. As a result, the acceleration will be constantly equal to 1 m/s².

Hence option c is correct.

To learn more about the force refer to the link;

brainly.com/question/26115859#SPJ1

#SPJ1

3 0

2 years ago