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Nastasia [14]
4 years ago
15

If a calibration curve of absorbance vs procaine hydrochloride concentration (mol L') is linear with the equation y = 240000x fo

r the derivatised procaine, what is the value of the molar absorptivity coefficient (Emolar)? Assume that a cuvette with a pathlength of 3 cm was used. (1 mark) Y=240000 Emolar = _ L molo
Physics
1 answer:
coldgirl [10]4 years ago
3 0

Answer:

8000 L/ mol cm is the value of the molar absorptivity coefficient.

Explanation:

The slope of the absorbance- concentration graph is equal to the product of path length and  molar absorptivity coefficient.

\frac{dA}{dc}=\epsilon l

\frac{dA}{dc}= Rate of change of absorbance with respect to concentration

\epsilon = molar absorptivity coefficient

l = Path-length

Given the slope of graph of absorbance vs procaine hydrochloride concentration.

y = 240000 x (linear equation)

Path length of cuvette = 3 cm

A=240000 c

A=\epsilon c\times l=(\epsilon l)\times c

240000=\epsilon \times 3

\epsilon =\frac{24000}{3}=8000

The units of \epsilon = 8000 l/mol cm

8000 L/ mol cm is the value of the molar absorptivity coefficient.

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Answer:

maximum height on moon is 6 times more than the maximum height on Earth

Explanation:

Let the Astronaut has its maximum speed by which he can jump is "v"

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now from above equation we will have

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H = \frac{v^2}{2g}

now if Astronaut jump on the surface of moon with same speed

then we know that the acceleration of gravity on surface of moon is 1/6 times the gravity on earth

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A car moving at 50 miles per hour speeds up steadily to 70 miles per hour over a period of 30 minutes. How far did it travel dur
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Answer:

The car will travel 30 miles during the 30-minutes period of acceleration.

Explanation:

Given data :

Initial velocity = v₁ = 50 miles/hour

Final velocity = v₂ = 70 miles/hour

Time = t = 30 min = 0.5 hour

Using the definition of acceleration, we find the acceleration (a)

                   a = (v₂ - v₁) ÷ t

                   a = (70 - 50) ÷ 0.5

                   a = 20 ÷ 0.5

                   a = 40 miles/hour²

Using 3rd equation of motion, we find the distance travel (s)

                    2as = v₂² -  v₁²

                    2(40)s = 70² - 50²

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Explanation:

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v = 1.86 x 10⁷ m /s

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V = 1.8 x 10⁶ volt .

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