<h2>
Answer:</h2>
The total number of different arrangements of 7 letters that are possible if the first letter will be w or k is:
617,831,552
<h2>
Step-by-step explanation:</h2>
The number of different arrangements of 7 letters can be formed if the first letter must be w or k such that the repetition of the letters are allowed are:
2×26×26×26×26×26×26
( Since, at the first place any of the 2 letter out of w or k could come up.
and from the second to seventh place any of the 26 letters of the English alphabet may come up )
Hence, total number of arrangements = 617,831,552
three consecutive integers
the sum of the first two integers is 24 more than the third integer.
This means that the three integers are 25, 26 and 27.
Answer:
12
Step-by-step explanation:
The cost for n attendees will be ...
cost = 2 + 2n
We want the cost to be, at most, 26, so we have ...
26 ≥ 2 +2n
Dividing by 2 gives ...
13 ≥ 1 + n
And subtracting 1, we find the answer:
12 ≥ n
At most, there can be 12 attendees.
Answer:
Not for sure but i think so
Step-by-step explanation:
