4 years ago

What are some ways living things can be grouped

Physics

1 answer:

marta [7]4 years ago

6 0

Living things can be grouped into five main groups called kingdoms: plants, animals, fungi, Protoctista and Monera.

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I lift a 100 kg mass to a height of 5 meters, how much work would i have none?

defon

Work=mass×gravity due to acceleration ×height
Work=100×9.8×5
Work=4900J

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4 years ago

Four identical resistors have 12 ohm each. Find the equivalent resistance Req when : (a) all four of them are connected in serie

Elanso [62]

Answer:

(a): When the four resistors are connected in series the equivalent resistor value is Req= 48Ω

(b): when the four resistors are connected in parallel the equivalent resistor value is Req=3Ω

Explanation:

R=R1=R2=R3=R4= 12Ω

(a)

Req= R1+R2+R3+R4

Req= 48 Ω

(b)

Req= (1/12 * 4)⁻¹

Req= 3 Ω

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3 years ago

Ryan hypothesizes that darker colors heat up faster. he places a thermometer inside a red wool sock, a green cotton glove, and a

solmaris [256]

There's no "control" they all differ. If they were all exactly the same size shape and material it would be doable.

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3 years ago

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A caterpillar climbs up a one-meter wall. For every 2 cm it climbs up, it slides down 1 cm. It takes 10 minutes for the caterpil

Brut [27]

100cm to go in 600 secs = 10mins

2 positive, 1 negative .... net 1 positive per step

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3 years ago

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A 10kg object experiences a horizontal force which causes it to accelerate 5 m/s2 moving it a distance of 20 m horizontally. How

mr_godi [17]

Answer:

The work done by the force is 1000 J.

Explanation:

Given:

Mass of object (m) = 10 kg

Acceleration of the object (a) = 5 m/s²

Displacement of the object (S) = 20 m

Using Newton's second law, we have:

Force = Mass × Acceleration

$F=ma$

Plug in the given values and solve for force 'F' acting on the object. This gives,

$F=(10\ kg)(5\ m/s^2)\\\\F=50\ N$

Now, work done by the force 'F' is equal to the product of force 'F' and the displacement it cause in its direction which is 20 m.

Therefore, the work done by the force is given as:

Work = Force × Displacement

$W=FS$

Plug in the values given and solve for 'W'. This gives,

$W=50\ N\times 20\ m \\\\W=1000\ J$

Therefore, the work done by the force is 1000 J.

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4 years ago