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NNADVOKAT [17]
3 years ago
13

Does the mass of a supermassive black hole correlate with any other part of a galaxy?

Physics
1 answer:
Gekata [30.6K]3 years ago
6 0
Based on my research, it is not correlated with any other part of a galaxy but the masses of supermassive black holes are known to correlate with the properties of the bulge components of their host galaxies. Then this supermassive black hole seems not to correlate with galaxy disks.
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A bird flies north 3 kilometers and then south 4 kilometers, what is the resultant displacement of the bird? Do not forget to in
Ber [7]

Answer: let north be+ and south be-

therefore, -1 km  is the resultant displacement of the bird

hope it helped u,

pls put thanks and pls mark as the brainliest

^_^

8 0
3 years ago
A plucked guitar string produces a sound wave with a wavelength of 0.15 m and a velocity of 10.5 m/s, what is the frequency of t
Leno4ka [110]
We know,
V= f× wavelength
10.5= f×0.15
f=10.5/0.15
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8 0
3 years ago
Un puente de acero de 100 m de largo a 8° C aumenta su temperatura a 24°C ¿Cuánto medirá su longitud? Valor del coeficiente de d
BartSMP [9]

La longitud <em>final</em> del puente de acero es 100.018 metros.

Asumamos que la dilatación <em>térmica</em> experimentada por el puente de acero es <em>pequeña</em>, de modo que podemos emplear la siguiente aproximación <em>lineal</em> para determinar la longitud <em>final</em> del puente de acero (L), en metros:

L = L_{o}\cdot [1+\alpha\cdot (T_{f}-T_{o})] (1)

Donde:

  • L_{o} - Longitud inicial del puente, en metros.
  • \alpha - Coeficiente de dilatación, sin unidad.
  • T_{o} - Temperatura inicial, en grados Celsius.
  • T_{f} - Temperatura final, en grados Celsius.

Si tenemos que L_{o} = 100\,m, \alpha = 11.5\times 10^{-6}, T_{o} = 8\,^{\circ}C y T_{f} = 24\,^{\circ}C, entonces la longitud final del puente de acero es:

L = (100\,m)\cdot [1+(11.5\times 10^{-6})\cdot (24\,^{\circ}C - 8\,^{\circ}C)]

L = 100.018\,m

La longitud <em>final</em> del puente de acero es 100.018 metros.

Para aprender más sobre dilatación térmica, invitamos cordialmente a ver esta pregunta verificada: brainly.com/question/24953416

5 0
2 years ago
Any help guys? I am stuck on two problems.
Juli2301 [7.4K]

Ax=A*Cos56

   = 20*(0.559)

   = 11.18 N

8 0
3 years ago
A 4400 W motor is used to do work. If the motor is used for 200 s, how much work could it do? (Power: P = W/t)
guajiro [1.7K]
So if p=w/t
then 4400=(w)(200)
so you would multiply 4440•200 and get 880,000
3 0
3 years ago
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