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NNADVOKAT [17]
3 years ago
13

Does the mass of a supermassive black hole correlate with any other part of a galaxy?

Physics
1 answer:
Gekata [30.6K]3 years ago
6 0
Based on my research, it is not correlated with any other part of a galaxy but the masses of supermassive black holes are known to correlate with the properties of the bulge components of their host galaxies. Then this supermassive black hole seems not to correlate with galaxy disks.
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Which of the following is an example of increasing friction intentionally? a. waxing skis b. adding grease to gears on a bike c.
Aleonysh [2.5K]
C i think that it tell me if its wrong
7 0
3 years ago
Five identical quintuplets leave earth when they reach the age of 21, in the year 2121. Each quintuplet goes on a spaceship jour
Elena-2011 [213]

Answer:

Explanation:

This is a problem based on time dilation , a theory given by Albert Einstein .

The formula of time dilation is as follows .

t₁ = \frac{t}{\sqrt{1-\frac{v^2}{c^2} } }

t is time measured on the earth and t₁ is time measured by man on ship .

A ) Given t = 20 years , t₁ = ? v = .4c

\frac{20}{\sqrt{1-\frac{.16c^2}{c^2} } }

=1.09 x 20

t₁= 21.82 years

B ) Given t = 5 years , t₁ = ? v = .2c

\frac{5}{\sqrt{1-\frac{.04c^2}{c^2} } }

=1.02 x 5

t₁= 5.1 years

C ) Given t = 10 years , t₁ = ? v = .8c

\frac{10}{\sqrt{1-\frac{.64c^2}{c^2} } }

=1.67 x 10

t₁= 16.7  years

D ) Given t = 10 years , t₁ = ? v = .4c

\frac{10}{\sqrt{1-\frac{.16c^2}{c^2} } }

=1.09 x 10

t₁= 10.9  years

E ) Given t = 20 years , t₁ = ? v = .8c

\frac{20}{\sqrt{1-\frac{.64c^2}{c^2} } }

=1.67 x 20

t₁= 33.4   years

7 0
3 years ago
Medical x-rays, with a wavelength of about 10^(-10) m, can penetrate completely through your skin.
natulia [17]
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= 10⁻⁷ m
4 0
3 years ago
What are forces that two objects apply on each other
liq [111]
Answer: Whenever two objects are touching, they usually exert forces on each other. The force of gravity, on the other hand, is an example of a force that exists between objects without them having to be in contact. Objects with mass exert forces on each other via the force of gravity.

HOPE IT HELPED:) HAVE A NICE DAY
3 0
3 years ago
The period T of a pendulum of length L is measured to determine g at the surface of Earth. The equation used is T=2π√L/g. The ma
saul85 [17]

Answer:

C: Variation in the value of g as the pendulum bob moves along its arc.

Explanation:

The formula for period of a simple pendulum is given by;

T = 2π√(L/g)

Where;

L is length

g is acceleration due to gravity

Now, from this period equation, it is clear that the only thing that can affect the period of a simple pendulum are changes to its length and acceleration due to gravity.

Looking at the options, the only one that talks about either the length or gravity as being potential causes of the error is option C

4 0
3 years ago
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