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koban [17]
3 years ago
15

The speed of a 180-g toy car at the bottom of a vertical circular portion of track is 7.75 m/s. If the radius of curvature of th

is portion of the track is 57.5 cm, what are the magnitude and direction of the force the track exerts on the car
Physics
1 answer:
Bezzdna [24]3 years ago
7 0

Answer:

11.28 N toward the center of the track

Explanation:

Centripetal force: This is the force that tend to draw a body close to the center of a circle, during circular motion.

The formula for centripetal force is given as,

F = mv²/r................................ Equation 1

Where F = force, m = mass of the toy car, v = velocity, r = radius

Given: m = 108 g = 0.108 kg, v = 7.75 m/s, r = 57.5 cm = 0.575 m

Substitute into equation 1

F = 0.108(7.75²)/0.575

F = 11.28 N

Hence the magnitude and direction of the force = 11.28 N toward the center of the track

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A steel aircraft carrier is 370 m long when moving through the icy North Atlantic at a temperature of 2.0 °C. By how much does t
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Answer:

The carrier lengthen is 0.08436 m.

Explanation:

Given that,

Length = 370 m

Initial temperature = 2.0°C

Final temperature = 21°C

We need to calculate the change temperature

Using formula of change of temperature

\Delta T=T_{f}-T_{i}

\Delta T=21-2.0

\Delta T=19^{\circ}C

We need to calculate the carrier lengthen

Using formula of length

\Delta L=\alpha_{steel}\times L_{0}\times\Delta T

Put the value into the formula

\Delta L=1.2\times10^{-5}\times370\times19

\Delta L=0.08436\ m

Hence, The carrier lengthen is 0.08436 m.

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3 years ago
If you drive 125 km in 2 hours, what is your average speed
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A girl and her bicycle have a total mads of 42 kg. At the top of the hill her speed is 4 m/s. The hill is 14.3m high and 112m lo
frosja888 [35]

Answer:

13.78 m/s

Explanation:

Given that:

The mass of the girl & her bicycle = 42 kg

The speed at the top of the hilll= 4 m/s

The height of the hill = 14.3 m

The length of the hill (distance) = 112 m

The frictional force = 20 N

To find the speed at the bottom of the hill; we need to carry out the following processes.

The workdone by gravity = mass × acceleration due to  gravity × Δh

= 42 × 9.8 × ( 14.3 - 0 )

= 5885.88 joules

The workdone by the friction = Force × distance = - 20 × 112    (since she is riding down the hill)

The workdone by the friction = -2240 Joules

The initial Kinetic friction = 1/2 mv²

= 1/2 × 42 × 4²

= 336 Joules

The final kinetic energy = Initial Kinetic energy + total work  

The final kinetic energy = (336 + 5885.88 - 2240) Joules

The final kinetic energy = 3981.88   Joules

Using the final kinetic energy =   1/2 mv²

3981.88  = 1/2 × 42 × v²

3981.88  = 21 v²

v² = 3981.88/21

v² =189.61

v = \sqrt{189.61}

v = 13.78 m/s

Therefore, the speed at the bottom = 13.78 m/s

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3 years ago
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What is the wavelength of a radiowave that has a frequency of 9.650 x10^7 Hz (cycles per second)?h = 6.6261 x10^-34 J/sc = 2.998
slava [35]

Hello!!

For this, we only need frequency and speed, so for calculate we applicate formula:

\boxed{\lambda = V/f}

\textbf{Being:}

\sqrt{} \lambda = Wavelength = \   ?

\sqrt{} V = Velocity = 2.998*10^{8} \ m/s

\sqrt{} f = Frequency = 9,650*10^{7} \ Hz

\text{Then let's \textbf{replace it according} we information:}

\lambda = 2,998*10^{8} \ m /s  / 9,650*10^{7} \ Hz

\lambda  =  3.106 \ m

\textbf{Result:}\\\text{The wavelength of the radiowave is \textbf{3.106 meters}}

4 0
3 years ago
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