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dimaraw [331]
3 years ago
5

Cross-training employees is only necessary in the genetic science industry. O True O False

Physics
2 answers:
zhannawk [14.2K]3 years ago
8 0

Answer: False

Explanation:  

Lelechka [254]3 years ago
7 0

Answer:

False

Explanation:

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A rollercoaster car has 2500 J of potential energy and 160 J of
Mrrafil [7]

Answer:

xaubUajnaai ajn AJ au aun a

Explanation:

ahayba uabah an aj

6 0
3 years ago
The initial kinetic energy imparted to a 0.25 kg bullet is 1066 J. The acceleration of gravity is 9.81 m/s 2 . Neglecting air re
lubasha [3.4K]

Answer:

The range of the bullet is 0.435 kilometers.

Explanation:

According to the problem, maximum height is equal to the range of the bullet. That is:

\Delta x = \Delta y

Where:

\Delta x - Range of the bullet, measured in meters.

\Delta y - Maximum height of the bullet, measured in meters.

By the Principle of Energy Conservation, gravitational potential energy reaches its maximum at the expense of the initial kinetic energy. That is to say:

K_{1} = U_{2}

Where:

K_{1} - Kinetic energy at point 1, measured in joules.

U_{1} - Gravitational potential energy at point 2, measured in joules, and:

U_{2} = m\cdot g \cdot \Delta y

Where:

m - Mass of the bullet, measured in kilograms.

g - Gravitational constant, measured in meters per square second.

The maximum height is now cleared:

K_{1} = m\cdot g \cdot \Delta y

\Delta y = \frac{K_{1}}{m\cdot g}

If K_{1} = 1066\,J, m = 0.25\,kg and g = 9.81\,\frac{m}{s^{2}}, the maximum height is now computed:

\Delta y = \frac{1066\,J}{(0.25\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}

\Delta y = 434.791\,m

\Delta y = 0.435\,km

Lastly, the range of the bullet is 0.435 kilometers.

3 0
3 years ago
contractor will use a package emulsion having a specific gravity of 1.25 and relative bulk strength of 130 to open an excavation
tester [92]

Answer:

The burden distance is 7 ft

Solution:

As per the question:

Specific gravity of package emulsion, SG_{E} = 1.25

Specific gravity of diabase rock, SG_{R} = 2.76

Diameter of the packaged sticks, d = 3 in

Now,

To calculate the first trail shot burden distance, B:

B = [\frac{2SG_{E}}{SG_{R}} + 1.5]\times d

B = [\frac{2\times 1.25}{2.76} + 1.5]\times 3 = 7.22

B = 7 ft

5 0
2 years ago
Which letter in the figure below marks 1 millimeter
kondor19780726 [428]
Do you have a picture then I could determine 1 millimeter
5 0
3 years ago
Moving a charged object against an electrical force causes it to
Alinara [238K]

Decelerate

<u>Explanation:</u>

If a charged object is moving against an electric force, the electric force would cause the charged object to decelerate. Rate of deceleration would depend on the amount of the charge the object posses and amount of the opposing electric force.

This could be understood by visualising a hypothetical situation where a charged object is moving against an electric force. Since the object is charged, it would exert a force in its direction of motion which would be opposed by the electric force, thus causing it to decelerate  

5 0
3 years ago
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