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3 years ago

Cross-training employees is only necessary in the genetic science industry. O True O False

Physics

2 answers:

zhannawk [14.2K]3 years ago

8 0

Answer: False

Explanation:

Lelechka [254]3 years ago

7 0

Answer:

False

Explanation:

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The talk test can be used to measure the __________. A. knowledge of an activity B. intensity of an activity C. length of an act

marta [7]

Answer:

Explanation:

According to CDC, if you’re doing moderate-intensity activity, you can talk but not sing during the activity.

8 0

3 years ago

Read 2 more answers

One hazard of space travel is the debris left by previous missions. There are several thousand objects orbiting Earth that are l

MariettaO [177]

Answer:

F = 6666.7 N

Explanation:

Given that,

Mass of a chip, m = 0.1 mg

Initial speed, u = 0

Final speed, $v=4\times 10^{3}\ m/s$

Time of collision, $t=6\times 10^{-8}\ s$

We know that,

Force, F = ma

Put all the values,

$F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.1\times 10^{-6}\times (4\times 10^3-0)}{6\times 10^{-8}}\\\\F=6666.7\ N$

So, the required force is 6666.7 N.

3 0

3 years ago

A block with mass m is pulled horizontally with a force F_pull leading to an acceleration a along a rough, flat surface.

Simora [160]

Answer:

$\mu_k=\frac{a}{g}$

Explanation:

The force of kinetic friction on the block is defined as:

$F_k=\mu_kN$

Where $\mu_k$ is the coefficient of kinetic friction between the block and the surface and N is the normal force, which is always perpendicular to the surface that the object contacts. So, according to the free body diagram of the block, we have:

$N=mg\\F_k=F=ma$

Replacing this in the first equation and solving for $\mu_k$ :

$ma=\mu_k(mg)\\\mu_k=\frac{a}{g}$

6 0

3 years ago

As a certain object falls, its position s (in meters) above ground after t seconds is given by s(t)=20-5t^2. Whats the average v

denpristay [2]

The average velocity of the object would be :

[s (1.5) - s (1)] / 0.5

= [8.75 -15] / 0.5

= 12.5 m/s

Hope this helps

3 0

3 years ago

1 2 3 4 5 6 7 8 9 10 TIME REMAINING 59:49 Which changes would result in a decrease in the gravitational force between two object

Masteriza [31]

Answer:

increasing the distance between the objects

decreasing the mass of one of the objects

decreasing the mass of both objects

Explanation:

The complete question would be:

Which changes would result in a decrease in the gravitational force between two objects? Check all that apply.

increasing the distance between the objects

decreasing the distance between the objects

increasing the mass of one of the objects

increasing the mass of both objects

decreasing the mass of one of the objects

decreasing the mass of both objects

---------------------------------------------------------------------------------------

Gravitational force between two objects can be computed using the formula:

$Fg = G\dfrac{Mm}{r^2}$

Where:

Fg is the gravitational force (Newtons or N)

G is the gravitational constant (6.674⋅10⁻¹¹N(m/kg)²)

M is the mass of one object (Kilograms or Kg)

m is the mass of the other object (Kilograms or Kg)

r is the distance between the two objects (m)

Now notice the relationship between the mass and gravitational force. Their relationship is direct, meaning as the value of one goes up, the other goes up and the reverse holds true. If the mass of one or both of the objects decreases, the gravitational force also decreases.

Now look at the relationship between the distance between the objects and the gravitational force-- they are indirect. This means that as one increases, the other decreases. So if we increase the distance between the objects, the gravitational force between them decreases as well.

3 0

3 years ago