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Monica [59]
4 years ago
10

how long is the shorter side of a rectangle when one side is 2" longer than the other and the area is 15 sq. in?

Mathematics
1 answer:
CaHeK987 [17]4 years ago
5 0
Technically 30. You do 15 x 2 which is 30.
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Mary had 25 marbles in a bag. The bag contains 10 red marbles, 7 blue marbles, and 8 green marbles. Mary pulled out two marbles
Mademuasel [1]

Answer:

Step-by-step explanation:

8/25 * 10/24 = 0.13333

4 0
3 years ago
Solve for X<br> Your answer must be simplified.<br><br> -7x &gt; 10
Bezzdna [24]

Answer:

There are many solution for this problem

The solutions are -2, -3, -4..... And even fractions like -11/7, -12/7, etc.

Hope this helps!

7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B7%7D" id="TexFormula1" title="\frac{n}{7}" alt="\frac{n}{7}" align="absmiddle
sashaice [31]

Answer:

n= -3.5

Step-by-step explanation:

n/7 - 12 = 5n +5

+12            +12

n/7 = 5n+17

*7      *7

n = (5n+17)*7

n = 35n + 119

-35n    -35n

-34n = 119

/-34     /-34

n = -3.5

3 0
3 years ago
Ecuación de la hipérbola con centro en (0;0), focos en abrir paréntesis 0 coma espacio menos raíz cuadrada de 28 cerrar paréntes
yaroslaw [1]

Answer:

\frac{y^{2}}{25}-\frac{x^{2}}{3}=1

Step-by-step explanation:

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

centro: (0,0)

focos: (0,-\sqrt{28}),(0,\sqrt{28})

eje conjugado = 2\sqrt{3}

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

de los focos podemos obtener que:

c=\sqrt{28}

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

b=\sqrt{3}

podemos utilizar la siguiente fórmula para obtener a:

c^{2}-a^{2}=b^{2}

si despejamos a en la ecuación obtenemos lo siguiente:

a=\sqrt{c^{2}-b^{2}}

ahora podemos sustituir los valores:

a=\sqrt{(\sqrt{28})^{2}-(\sqrt{3})^{2}}

a=\sqrt{28-3}

a=\sqrt{25}

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

\frac{y^{2}}{(5)^{2}}+\frac{x^{2}}{(\sqrt{3})^{2}}=1

\frac{y^{2}}{25}+\frac{x^{2}}{3}=1

si graficamos la hipérbola, queda como en el documento adjunto.

7 0
3 years ago
How many 8's are in the answer and sum 5890/45?
Simora [160]

Answer:

  It depends on how you write it.

  • 130 8/9 -- one 8
  • 130.88888888888... -- an infinite number of 8s

Step-by-step explanation:

The quotient 5890/45 has a value of 130 8/9. The fraction 8/9 is the repeating decimal 0.888888..., which has as many 8s as you want to write. It can be abbreviated to have just one 8 when written like this:

  130.\overline{8}

where the overbar indicates the digit repeats indefinitely.

The quotient can be written with as many 8s as you like.

6 0
4 years ago
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