3 years ago

How can you compare 7/10 and 1/2 without using a model?

Mathematics

1 answer:

yawa3891 [41]3 years ago

4 0

Seventy-three is the answer

You might be interested in

Can anyone help me? I'm not getting anywhere!!

hram777 [196]

To analyze [insert whatever box and whisker plot does] and compare.

7 0

2 years ago

Make C the subject of the formula:<br> F=9/5 C + 32

Dafna1 [17]

1)-9/5C=-F+32
2)9/5C=F-32
3)9C=5(F-32)
4)C=5/9(F-32)

4 0

2 years ago

I need help can some please answer this 2 2/3+1 1/2

irakobra [83]

Answer:

25/6 or 4 1/6

Step-by-step explanation:

1) convert these fractions to improper fractions first:

8/3+3/2

make like denominators by multiplying 8/3 by 2 and 3/2 by 3

so 8*2/3*2=16/6

3*3/2*3=9/6

16/6+9/6=25/6

Hope this helps!

3 0

3 years ago

Read 2 more answers

A family wants to save for college tuition for their daughter. What continuous yearly interest rate r% is needed in their saving

sergey [27]

Answer:

The continuous yearly interest is 22.5% per year.

Step-by-step explanation:

Continuous yearly interest:

Continuous yearly interest is defined as the sum of the interest comes from principle and the interest comes from interest.

The formula for continuous interest yearly is

$A=Pe^{rt}$

where A = The final amount =$110,000

P= principle =$4,700

r= rate of interest

t= time (in year)= 14 years

$\therefore 110,000= 4,700e^{r\times 14}$

$\Rightarrow e^{14r}= \frac{110,000}{4,700}$

Taking ln both sides

$\Rightarrow ln e^{14r}= ln(\frac{110,000}{4,700})$

$\Rightarrow {14r}= ln(\frac{1100}{47})$

$\Rightarrow r=\frac{ln( \frac{1100}{47})}{14}$

$\Rightarrow r = 0.225$ (approx)

The continuous yearly interest is 0.225 = 22.5% per year.

4 0

2 years ago

suppose linda had 2/3 of a yard of fabric and told Sandra that she used 3/4 of a yard. Sandra says this is not possible. Do you

zepelin [54]

I do not agree because 3/4 is greater than 2/3 so you can not do 3/4-2/3

7 0

3 years ago