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Liula [17]
3 years ago
6

The process of removing an electron from a stable nucleus is known as

Chemistry
1 answer:
larisa [96]3 years ago
3 0
The process of removing an electron form a stable nucleus is known as ionization energy. I hope this answered your inquiry, and if you require further assistance feel free to ask.
You might be interested in
Why would an atom emit particles or waves from its nucleus?
Neko [114]

Answer:

It’s A non of these

Explanation:

5 0
3 years ago
Calculate the percentage of calcium in calcium chlorate
givi [52]

Answer:

19.4%

Explanation:

Calcium Chlorate is Ca(ClO3)2

Now calculate the molar mass of Ca(ClO3)2

Ca = 40.1

Cl = 35.5

O = 16.0

But they are two chlorine atoms and six oxygen atoms. So you do this:

40.1 + 35.5(2) + 16.0(6) = 207.1 grams

Now find the molar mass of just calcium.

There is only one calcium atom.

So you do this.

40.1(1) = 40.1

Now divide the molar mass of calcium by the molar mass of calcium chlorate.

40.1 / 207.1 = 0.1936

0.1936 rounds to 0.194

Now multiply 0.194 * 100 and you will get 19.4

So the final answer is 19.4%.

Hope it helped!

4 0
3 years ago
Which of these methods could are used to separate an insoluble solid and soluble solid
olasank [31]

Answer:

To separate an insoluble solid from a soluble solid: Mixing the mixture with water, filtering out the insoluble solid, and then evaporating the water to isolate the soluble solid.

Explanation:

5 0
3 years ago
Will salivary amylase work in the stomach?​
lions [1.4K]

Answer:

Typically the pH in the stomach is around 1.0 to 2.0, which is extremely acidic. This level of acidity causes salivary amylase's protein structure to denature and change shape. Consequently, salivary amylase does not function once it enters the stomach.

Explanation:

7 0
3 years ago
a hydrogen-filled balloon was ignited and 1.60g of hydrogen reacted with 12.8g of oxygen. how many grams of water vapor were for
Anon25 [30]
2H2 + O2 ---> 2H2O

1 mole of H2 = 2g
1 mole of O2 = 32g
1 mole of H2O = 18g

according to the reaction:
2*2g H2---------------32g O2
1,6g H2----------------- x g O2
x = 12,8g O2

so reaction is stechiometric

32g O2---------------- 2*18g H2O
12,8g O2 -------------- x
x = 14,4g H2O

answer: 14,4g of water vapour
6 0
3 years ago
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