Q = mass x specific heat x delta T 343 = 55.0 x specific heat ( 86.0 - 19.0 ) 343 = 3685 x specific heat specific heat = 0.0931 cal /g°C
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Your answer is: 0.0931 cal/g degrees C
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Answer:
Oxygen gas
Explanation:
Potassium chlorate KClO3 decomposes thermally to form potassium chloride KCl and oxygen gas is given off. This is in the presence of a catalyst, manganese iv oxide.
Hence, what is being said in essence is that when potassium chloride is heated in the presence of manganese iv oxide catalyst, oxygen is given off as the gaseous product with the formation of potassium chloride.
The chemical equation for the reaction is :
2KClO3 ——-> 2KCl + 3O2
This procedure is one of most important ways through which oxygen can be produced in the laboratory and can be used as a source of oxygen is industrial processes if on a large scale
I dont know anything about this since i am not in college or high school i am in Middle school but I hope I will learn it
Answer:
The Two reasons are :-
1. Combustion efficiency
2. Standardization of test conditions as non-luminous flame.
Explanation:
A luminous flame isn't suitable for heating as it gives out soot (A black powdery or flaky substance consisting largely of amorphous carbon, produced by the incomplete burning of organic matter)
