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ra1l [238]
3 years ago
10

Can you always tell by looking at a substance if it is pure or not? ​

Chemistry
1 answer:
Hunter-Best [27]3 years ago
5 0

Answer:

nope

Explanation:

bcoz every thing we look that isn't real. some substance are chemically changed and some are physically changed.if the physical change occurs then it is temporary change and if chemical change occurs it is permanent change.

Conclusion:I can think this much with my tiny mind.

THANK YOU

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What is sometimes described as the ability to do work?
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Kinetic and potential energy
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3 years ago
How many moles of ammonia are in 735. mL of a 4.25 M aqueous ammonia solution?
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Answer:

*moles = molarity(M=moles/L) * volume (L)

so, you have 4.25 * 0.735 moles

*NH3

* M=n/v

*To determine the number of significant figures in a number use the following 3 rules: Non-zero digits are always significant. Any zeros between two significant digits are significant. A final zero or trailing zeros in the decimal portion ONLY are significant.

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Identify the functional groups attached to the benzene ring as either, being electron withdrawing, electron donating, or neither
Dominik [7]
-OH is elctron donating  -C=-N is electron withdrawing  -O-CO-CH3 is electron withdrawing  -N(CH3)2 is electron donating  -C(CH3)3 is electron donating  -CO-O-CH3 is electron withdrawing  -CH(CH3)2 is electron donating  -NO2 is electrong withdrawing  -CH2
8 0
4 years ago
Morphine is an effective pain killer but is also highly addictive. calculate the ph of a 0.115 m solution of morphine if its pkb
VMariaS [17]

Answer is: pH value of morphine is 10.64.<span>
Chemical reaction: </span>C₁₇H₁₉NO₃ + H₂O → C₁₇H₁₉NO₃H⁺ +OH⁻.<span>
Kb(</span>C₁₇H₁₉NO₃) = 10∧(-5,79) = 1,62·10⁻⁶.<span>
c(</span>C₁₇H₁₉NO₃<span>) = 0,115 M.</span><span>
Kb(</span>C₁₇H₁₉NO₃) = c(OH⁻) · c(C₁₇H₁₉NO₃H⁺) ÷ c(C₁₇H₁₉NO₃).<span>
c(OH</span>⁻) = c(C₁₇H₁₉NO₃H⁺) = x.
1,62·10⁻⁶<span> = x² ÷ (0,115 - x).</span><span>
Solve quadratic equation: x = c(OH</span><span>⁻) = </span><span>0,000431 M.
pOH = -log(</span>0,000431 M<span>) = 3,36.
pH = 14 - 3,36 = 10,64.</span>

5 0
3 years ago
The sun supplies about 1.0 kilowatt of energy for each square meter of surface area (1.0 kW/m^2 where a watt = 1 kJ/s) Plants pr
kaheart [24]

Answer:

0.092 %

Explanation:

The equation of the reaction can be computed as :

12CO_2_{(g)} + 11H_2O_{(l)} \to C_{12}H_{22}O_{11} + 12O_{2_(g)}

\Delta H = 5645 \ kJ

recall that; the number of moles = \dfrac{mass}{molar \ mass}

By applying the method of enthalpy of combustion for sucrose at the same time changing the time from hours to seconds, we can determine the total energy output.

i.e

=\dfrac{0.20g \ of \ sucrose }{m^2 \ 3600 \ s}\times \dfrac{1 \ mol}{342.34 \ g}\times 5.645 kJ/mol

= 9.16 \times 10^{-4} \ kJ/m^2 s

Given that the sun supplies about 1.0 kilowatt, to KJ/m² s, we have:

1.0 \dfrac{kW}{m^2 }= 1.0 \dfrac{kJ}{m^2 s}

Finally, the percentage of sunlight used to produce sucrose :

= \dfrac{9.16 \times 10^{-4} \ kJ/m^2 \ s}{1.0 \ kJ/m^2 . s} \times 100\%

= 0.092 %

6 0
3 years ago
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