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ra1l [238]
3 years ago
10

Can you always tell by looking at a substance if it is pure or not? ​

Chemistry
1 answer:
Hunter-Best [27]3 years ago
5 0

Answer:

nope

Explanation:

bcoz every thing we look that isn't real. some substance are chemically changed and some are physically changed.if the physical change occurs then it is temporary change and if chemical change occurs it is permanent change.

Conclusion:I can think this much with my tiny mind.

THANK YOU

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Draw the structures of the major 1,2 and 1,4-products formed by reaction of 1 mole of Br2 with 3-methyl-2,4-hexadiene. Assume th
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8 0
3 years ago
an unknown sample required 21.05 mL of 0.02047 M KmnO4 to reach the end point. How many moles of KmnO4 reacted?
Angelina_Jolie [31]
.02047 = x / 0.02105 = 0.0004309mol
6 0
3 years ago
What is the difference between ionization energy and ionization potential​
rjkz [21]

Answer:

They are similarly

Explanation:

3 0
3 years ago
nswer the following questions relating to HCl, CH3Cl, and CH3Br.HCl(g), can be prepared by the reaction of concentrated H2SO4(ag
alexdok [17]

Answer:

It is an example of double displacement reaction.

4.8 g of NaCl is needed to react.

Explanation:

Balanced reaction: H_{2}SO_{4}(aq.)+2NaCl(s)\rightarrow 2HCl(g)+Na_{2}SO_{4}(aq.)

Here, oxidation states of H, S, O, Na and Cl do not change during reaction. Hence it is not a redox reaction.

In this reaction, cations and anions of the reactants interchange their partners during reaction. Hence, it is an example of double displacement reaction.

As H_{2}SO_{4}(aq.) remain in excess amount therefore NaCl (s) is the limiting reagent. Hence production of HCl entirely depends on amount of NaCl used.

Molar mass of HCl = 36.46 g/mol

So, 3.0 g of HCl = \frac{3.0}{36.46} mol of HCl = 0.082 mol of HCl

According to balanced equation-

2 moles of HCl are produced from 2 moles of NaCl

So, 0.082 moles of HCl are produced from 0.082 moles of NaCl

Molar mass of NaCl = 58.44 g/mol

So, mass of 0.082 moles of NaCl = (0.082\times 58.44) g = 4.8 g

Hence 4.8 g of NaCl is needed to react.

4 0
4 years ago
If you have 40 grams of potassium nitrate in 100 grams of water at 20 C:
anygoal [31]

Answer:

Explanation:The final homogenous solution, after cooling it to 40°C, will contain 47 g of potassium sulfate disolved in 150 g of water, so you can calculate the amount disolved per 100 g of water in this way:

[47 g of solute / 150 g of water] * 100 g of g of water = 31.33 grams of solute in 100 g of water.

So, when you compare with the solutiblity, 15 g of solute / 100 g of water, you realize that the solution has more solute dissolved with means that it is supersaturated.

To make a saturated solution, 15 grams of potassium sulfate would dissolve in 100 g of water.

Read more on Brainly.com - brainly.com/question/5143785#readmore

7 0
3 years ago
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