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Sati [7]
3 years ago
15

A block with mass M is placed on an inclined plane with slope angle q and is connected to a second hanging block with mass m by

a cord passing over a small, frictionless pully. The coefficient of static friction μs and the coefficient of kinetic friction is μk. For what range values of of m will the blocks remain at rest if they are released from rest.

Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
7 0

Answer:

The mass of the block m is:

m=M(sin(\theta)+\mu_{s}cos(\theta))

Explanation:

Let's analyze the block by parts

For the block M

T-W_{x}-f_{f}=0 (1)

Where:

  • T is the tension
  • W(x) is the component of the weight in the x-direction
  • F(f) is the friction force

T-Mgsin(\theta)-\mu_{s}N=0  

T-Mgsin(\theta)-\mu_{s}Mgcos(\theta)=0  

For the block m

T-W=0

T=mg (2)

Now, let's combines equation (1) and (2):

mg-Mgsin(\theta)-\mu_{s}Mgcos(\theta)=0  

Finally, let's solve it for block m.

mg-Mg(sin(\theta)+\mu_{s}cos(\theta))=0

m=M(sin(\theta)+\mu_{s}cos(\theta))

I hope it helps you!

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4 years ago
An energy plant produces an output potential of 1500 kV and serves a city 143 km away. A high-voltage transmission line carries
jekas [21]

Answer:

2123.55 $/hr

Explanation:

Given parameters are:

V_{plant} = 1500 KV

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I = 500 A

\rho = 2.4 \Omega / km

So, we will find the voltage potential provided for the city as:

V_{wire} =IR = I\rho L = 1500*2.4*143 = 514.8 kV

V_{city} = V_{plant}- V_{wire} = 1500-514.8 = 985.2 kV

Then, we will find dissipated power because of the resistive loss on the transmission line as:

P = I^2R = I^2\rho L=500^2*2.4*143 = 8.58*10^7 W

Since the charge of plant is not given for electric energy, let's assume it randomly as x =  \frac{\dollar 0.081}{kW.hr}

Then, we will find the price of energy transmitted to the city as:

Cost = P * x = 8.58*10^7 * 0.081 * 0.001 = 6949.8 $/hr

To calculate money per hour saved by increasing the electric potential of the power plant:

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I_{new} = P/V_{new} = I/1.2\\P_{new} = I_{new}^2R_{wire}\\Cost = P_{new}/1.44=6949.8/1.44 = 4826.25 $/hr

The amount of money saved per hour = 6949.8 - 6949.8/1.44 = 2123.55 $/hr

Note: For different value of the price of energy, it just can be substituted in the equations above, and proper result can be found accordingly.

3 0
3 years ago
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Answer:

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Newton's law of cooling

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now by removing proportionality sign

\dfrac{dT}{dt}=-k(T-T_o)

Now by separating variables

\dfrac{dT}{(T-T_o)}=-k\ dt

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4 0
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Wittaler [7]

Answer:

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