First distribute the -3 to the 8 and -11y
so - 13y -24 +33y
combine like terms
so -13y and 33y together
that will be 20y -24
Hope this helps ;)
Answer:
The value of 
.
The value of 
.
Step-by-step explanation:
Consider the provided information.
The number of hours between successive train arrivals at the station is uniformly distributed on (0, 1). Passengers arrive according to a Poisson process with rate 7 per hour.
Let X denote the number of people who get on the next train.
Part (A)
Here, X = N(T), N(t) ∼ Poisson(λt), and λ = 7
Therefore, E(N(T)|T) = λT
Now find E(X) as shown below
Hence, the value of .
Part (B)
Now we need to find VAR[X]
Hence, the value of
Answer:
Rocco runs 7/9 laps per minute
Step-by-step explanation:
9 minutes ---> 7 laps
1 minute --> 7/9 laps
Answer: The correct answer is: [B]:
_________________________________________
" 
" .
_________________________________________
Step-by-step explanation:
_________________________________________
Note: A number; "divided by a variable" ; is Not a "polynomial" .
Answer choice: [B]: " " ;
is a "number; divided by a "variable" ; and as such, is Not a "polynomial".
_________________________________________
The solution is:A mole of gas occupies 22.4 L A liter is 1000 cubic centimeters because 1 cubic centimeter = 1 mL
One Helium molecule (essentially one helium atom) has atomic mass 4 g/mol So for every 22400 cubic centimeters of volume, we have 4 grams of helium Density of helium = 4g / 22400 cm^3 = 1g / 5600 cm^3
Volume of a sphere = (4/3)(pi)r^3 Volume of the outside sphere (the entire sphere) is (4/3)(pi)(R+T)^3 Volume of the inside sphere (the hollow region) is (4/3)(pi)R^3
The difference for the volume of silver. (4/3)(pi)(R+T)^3 - (4/3)(pi)R^3 = (4/3)(pi)(3R^2T + 3RT^2 + T^3)
The density of silver is 10.5g/cm^3
So the mass of the silver is computed by:10.5*(4/3)(pi)(3R^2T + 3RT^2 + T^3) = (14*pi)(3R^2T + 3RT^2 + T^3) = (14pi)T(3R^2 + 3RT + T^2)
Now for the mass of helium: volume x density = (4/3)(pi)R^3 (1/5600) = (pi/4200)R^3
Set the two masses equal: (pi/4200)R^3 = (14pi)T(3R^2 + 3RT + T^2) R^3 = 58800*T(3R^2 + 3RT + T^2) R / T = 58800*(3R^2 + 3RT + T^2) / R^2 = 58800*( 3+T/R^2+(T/R)^2)
then solve for xx = T / R 1/x = 58800*( 3+x/R+x^2) 1/58800 = x (3 + x/R + x^2) 1/58800 = 3x + x^3 x^3 + 3x - 1/58800= 0 x = ~ 5.66893x10^(-6)
