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omeli [17]
3 years ago
7

For this problem, you will want to guess and check until you find the right solution. How many years does it take for $100 to re

ach $1 million dollars? The rate is at 5% with it being compounded twice a year. Round to a whole year. Hint: You may want to start with numbers above 100 years!\
Mathematics
2 answers:
nikitadnepr [17]3 years ago
8 0

Answer:

189 years = 1011061.38575 = 1 million, 11 thousand and 61 and 38 rounded up to 2dp $35011061.39

Step-by-step explanation:

100(1 + 0.05)^188=962915.605474

100(1 + 0.05)^189=1011061.38575

It cannot be 188 years.

But if we tried 189 this would make just over 1 million.= $10011061.36

algol [13]3 years ago
6 0

Step-by-step explanation:

1 Million = 1,000,000

100 x 5% = 5

100 - 5 = 95

1,000,000 divided by 95

10526.3157895 (Round it)

10526 years

(MIGHT BE INCORRECT)

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solniwko [45]

3x^2\div(x-2)+x^2\div(x-2)=\dfrac{3x^2}{x-2}+\dfrac{x^2}{x-2}=\dfrac{4x^2}{x-2}

6 0
3 years ago
A recent study suggested that 70% of all eligible voters will vote in the next presidential election. Suppose 20 eligible voters
natita [175]

Answer:

0.0479 = 4.79% probability that fewer than 11 of them will vote

Step-by-step explanation:

For each voter, there are only two possible outcomes. Either they will vote, or they will not. The probability of a voter voting is independent of any other voter, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

70% of all eligible voters will vote in the next presidential election.

This means that p = 0.7

20 eligible voters were randomly selected from the population of all eligible voters.

This means that n = 20

What is the probability that fewer than 11 of them will vote?

This is:

P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{20,10}.(0.7)^{10}.(0.3)^{10} = 0.0308

P(X = 9) = C_{20,9}.(0.7)^{9}.(0.3)^{11} = 0.0120

P(X = 8) = C_{20,8}.(0.7)^{8}.(0.3)^{12} = 0.0039

P(X = 7) = C_{20,7}.(0.7)^{7}.(0.3)^{13} = 0.0010

P(X = 6) = C_{20,10}.(0.7)^{6}.(0.3)^{12} = 0.0002

P(X = 5) = C_{20,5}.(0.7)^{5}.(0.3)^{15} \approx 0

The probability of 5 or less voting is very close to 0, so they will not affect the outcome. Then

P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0) = 0.0308 + 0.0120 + 0.0039 + 0.0010 + 0.0002 = 0.0479

0.0479 = 4.79% probability that fewer than 11 of them will vote

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tatuchka [14]

Answer:

Yes 10.7

Step-by-step explanation:

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3 years ago
1. Graphs of two trigonometric functions are shown below
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Answer:

its correct bye tanks for the points

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3 years ago
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