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Lunna [17]
3 years ago
13

In which species does sulfur have the highest oxidation number? s8 (elemental form of sulfur) h2s so2 h2so3 k2so4?

Chemistry
1 answer:
Mashutka [201]3 years ago
8 0
There are rules to assigning conventional oxidation numbers to some elements. For those unspecified, you can solve them. This is how you solve it.

*S8. Since this is in elemental form, its oxidation number is assigned as 0.

*H2S. H is assigned with +1. Since the compound is neutral, the overall charge is 0. So,
2(+1) + x = 0
x = -2
The charge of S here is -2.

*SO₂. O is assigned with (-2). Using the same procedure,
x + 2(-2) = 0
x = +2
The charge of S here is +2.

*H₂SO₃.
2(+1) + x + 3(-2) = 0
x = +4.
The charge of S here is +4.

*K₂SO₄. K is assigned with +1. 
2(+1) + x + 4(-2) = 0
x = +6
The charge of S here is +6.

<em>The S with the highest oxidation number is the one in K₂SO₄.</em>

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Determine the root-mean square speed of CO2 molecules that have an average kinetic energy of 4.2 x10-21 J per molecule.
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<span>Determine the root-mean-square sped of CO2 molecules that have an average Kinetic Energy of 4.21x10^-21 J per molecule. Write your answer to 3 sig figs.
</span><span>
E = 1/2 m v^2 

If you substitute into this formula, you will get out the root-mean-square speed. 

If energy is Joules, the mass should be in kg, and the speed will be in m/s. 

1 mol of CO2 is 44.0 g, or 4.40 x 10^1 g or 4.40 x 10^-2 kg. 

If you divide this by Avagadro's constant, you will get the average mass of a CO2 molecule. 

4.40 x 10^-2 kg / 6.02 x 10^23 = 7.31 x 10^-26 kg 

So, if E = 1/2 mv^2 

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8 0
3 years ago
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Dahasolnce [82]

Answer:

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6 0
2 years ago
Choose the correct simplification of<br>x^12z^11/x^2z^4<br>​
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━━━━━━━☆☆━━━━━━━

▹ Answer

<em>x¹⁰z¹⁵</em>

▹ Step-by-Step Explanation

x¹²z¹¹/x²z⁴

<u>Reduce</u>

x¹⁰z¹¹ * z⁴

<u>Calculate</u>

x¹⁰z¹⁵

Hope this helps!

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Brainliest is greatly appreciated!

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5 0
3 years ago
what mass of carbon dioxide will be produced when 12.9 g of butane reacts with an excess of oxygen in the following reaction?
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3 0
3 years ago
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