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Lunna [17]
3 years ago
13

In which species does sulfur have the highest oxidation number? s8 (elemental form of sulfur) h2s so2 h2so3 k2so4?

Chemistry
1 answer:
Mashutka [201]3 years ago
8 0
There are rules to assigning conventional oxidation numbers to some elements. For those unspecified, you can solve them. This is how you solve it.

*S8. Since this is in elemental form, its oxidation number is assigned as 0.

*H2S. H is assigned with +1. Since the compound is neutral, the overall charge is 0. So,
2(+1) + x = 0
x = -2
The charge of S here is -2.

*SO₂. O is assigned with (-2). Using the same procedure,
x + 2(-2) = 0
x = +2
The charge of S here is +2.

*H₂SO₃.
2(+1) + x + 3(-2) = 0
x = +4.
The charge of S here is +4.

*K₂SO₄. K is assigned with +1. 
2(+1) + x + 4(-2) = 0
x = +6
The charge of S here is +6.

<em>The S with the highest oxidation number is the one in K₂SO₄.</em>

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3 years ago
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Answer:

1 unit

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Explanation : Given,

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Formula used :

\text{Molarity}=\frac{\text{Mass of unknown substance}\times 1000}{\text{Molar mass of unknown substance}\times \text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

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Therefore, the molar mass of unknown substance is, 39.7 g/mol

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