When a non volatile solute is added to a solvent, the vapor pressure of the solvent will decrease.
Vapor pressure is a colligative property. Which means that it will be affected by the number of particles of solute.
The relationship between the concentration of the solute and the vapor pressure is given by Roult's Law
ΔP = Xsolute * P, where ΔP is vapor pressure lowering, Xsolute is the molar fractionof the solute, and P is the vapor pressure of the solvent.
Then lets find Xsolute
X solute = # moles solute / # moles solution
# moles solute = 75.0 grams / molar mass
molar mass of C12H22O11 = 12*12g/mol + 22*1g/mol + 11*16g/mol = 342 g/mol
# moles solute = 75.0/342 mol = 0.219 mol
# moles of solvent = grams of solvent / molar mass of solvent
# moles of solvent = 180 grams /18 g/mol = 10 mols
Xsolute = 0.219 mol solute / (10 + 0.219) mol solution =0.0215
ΔP = 0.0215*26.7 torr = 0.57 torr
Answer= 0.57 torr
Answer:
677.76 g of oxygen needed.
Explanation:
Given data:
Mass of glucose = 635.2 g
Mass of oxygen needed = ?
Solution:
Chemical equation:
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + energy
Number of moles of glucose:
Number of moles = mass/ molar mass
Number of moles = 635.2 g / 180.156 g/mol
Number of moles = 3.53 mol
Now we will compare the moles of glucose with oxygen.
C₆H₁₂O₆ : O₂
1 : 6
3.53 : 6×3.53 = 21.18 mol
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 21.18 g × 32 g/mol
Mass = 677.76 g
Density = mass / volume
1.5 = m / 50.0
m = 1.5 x 50.0
m = 75 g
hope this helps!
A straight line shows a direct proportion because each x-value has one y-value, and there is a correlation between the two values, not just random placement. Hope this helps! :)
