1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rom4ik [11]
3 years ago
15

A beta particle has

Chemistry
1 answer:
JulsSmile [24]3 years ago
5 0

Explanation:

Beta particles have a mass which is half of one thousandth of the mass of a proton and carry either a single negative (electron) or positive (positron) charge. As they have a small mass and can be released with high energy, they can reach relativistic speeds (close to the speed of light).

You might be interested in
Select the correct answer.
matrenka [14]

Answer:

At equilibrium the rate of the forward reaction is equal to the rate of the backward reaction.

When the product of a reaction at equilibrium is increased the equilibrium will shift left or to the reactant side. As a result the excess product will get converted to reactant. This is in accordance to Le Chatelier's principle.

Le Chatelier's principle states that when a system is subjected to stress the equilibrium will shift in a direction to minimize effect of the stress.

Thus the products added to the system at equilibrium will make the equilibrium shift to the reactant side, the rate of the reverse or backward reaction will increase.

Explanation:

Hope This Helps Amigo!

5 0
3 years ago
What is the answer please
xeze [42]

Answer:

Selenium

Explanation:

Oxygen is present in the group sixteen.

This group consist of oxygen, sulfur, selenium, tellurium and polonium.

All of these have same number of valance electrons thus they show similar properties.

From the given list of elements only selenium is belong to oxygen family thus it has properties similar to the oxygen.

Electronic configuration of oxygen:

O = [He] 2s² 2p⁴

Electronic configuration of selenium:

Se = [Ar] 3d¹⁰ 4s² 4p⁴

While aluminium, boron and phosphorus are belongs to other groups that's why their properties are not similar to the phosphorus.

phosphorus is present in group 15.

Boron and aluminium are present in group 13.

6 0
4 years ago
How to find effective nuclear charge
kiruha [24]
The effective nuclear charge is the net positive charge experienced by valence electrons
3 0
3 years ago
Most homes are built with some form of insulation separating the inside of the home from the outside. What does this insulation
Ad libitum [116K]

Answer:

A. It decreases the temperature difference between the outside and inside.

Explanation:

6 0
2 years ago
Calculate the number of moles of each compound, given the number of molecules.
anastassius [24]

Answer:

1.  2.46\times 10^{21} molecules of CO₂

2. 10⁴ molecules of H₂O

3. 8.75×10³² molecules of C₆H₁₂O₆

Explanation:

1.  2.46\times 10^{21} molecules of CO₂

2. 10⁴ molecules of H₂O

3. 8.75×10³² molecules of C₆H₁₂O₆

5 0
3 years ago
Other questions:
  • Question 1 (1 point)
    11·1 answer
  • In the formula for carbon tetrahydride, CH4, the percent composition of all elements is:
    10·2 answers
  • What is the role of energy in forming bonds, and what is the role of energy in breaking bonds?​
    12·1 answer
  • What is the term for a solid that forms when two solutions are mixed?
    11·2 answers
  • What is the symbol for the ion that contains 12 protons, 10 electrons, and 12 neutrons?
    6·1 answer
  • Predict the shape and hybridization of platinum tetrachloride (PfCl4)​
    15·1 answer
  • Which of the following is an
    7·2 answers
  • Jane has a weight of 500 N. The area of her two feet is 250 cm2. The pressure when she is standing is Pressure = 500/250 = 2 N/c
    15·1 answer
  • Can someone pls help with the first two fill in the blanks
    8·1 answer
  • One of the basic building blocks of matter, which cannot be broken down by chemical means is a(n)______ , of which there are 92
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!