Answer:
All points on line CD are equidistant from A and B
Step-by-step explanation:
Given that point A is the center of circle A and point B is the center of circle B, and the circumference of circle A passes through the center of circle B which is point B and vice versa.
Therefore we have;
The radius of circle A = The radius of circle B
Which gives;
The distance of the point C to the center A is equal to the distance of the point C to the center B
Similarly, the distance of the point D to the center A is equal to the distance of the point D to the center B
So also the distances of all points on the line from the center A is equal to the distances of all points on the line from the center B.
the answer for this would be the last one. two rays that meet at a end point.
hope this helps!
Answer:
4
Step-by-step explanation:
break the first 2 into its components, 1 and 1 because 1 + 1 = 2.
Break the second 2 into its components, 1 and 1 because 1 + 1 = 2.
Combine all the components. Since they're all ones, you just have to count your fingers 4 times!
1 + 1 = 2. 2 + 1 = 3. 3 + 1 = 4!
1 + 1 + 1 + 1 = 4!
4 is the correct answer.
Answer:
The domain is "all real numbers" and the range is x more than -3
