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garik1379 [7]
3 years ago
14

Determine if the graph is symmetric about the x-axis, the y-axis, or the origin. r = 2 cos 5θ

Mathematics
2 answers:
Finger [1]3 years ago
5 0

Answer:

The graph is symmetric about the x-axis.

Step-by-step explanation:

1. Symmetry about the x-axis: If the point (r, θ ) lies on the graph, then the point  (r, -θ ) or (-r, π - θ ) also lies on the graph.

2. Symmetry about the y-axis: If the point (r, θ ) lies on the graph, then the point (r,  π - θ ) or (-r, -θ ) also lies on the graph.

3. Symmetry about the origin: If the point (r, θ ) lies on the graph, then the point (-r, θ ) or (r, π + θ ) also lies on the graph.

The given polar equation is

r=2\cos (5\theta)

Check the equation by (r, -θ).

r=2\cos (-5\theta)=2\cos (5\theta)=r

Therefore, the graph is symmetric about the x-axis.

Check the equation by (-r, -θ).

-r=2\cos (-5\theta)=2\cos (5\theta)=r\neq -r

Therefore, the graph is not symmetric about the y-axis.

Check the equation by (-r, θ).

-r=2\cos (5\theta)=2\cos (5\theta)=r\neq -r

Therefore, the graph is not symmetric about the origin.

murzikaleks [220]3 years ago
3 0
Looking at the graph, we'll notice that there is a local maximum at x=0 and it looks similar on both sides of the y axis, therefore making it symmetric around the y axis given the options
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\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
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n=
\begin{array}{llll}
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t=years\to &13
\end{cases}
\\\\\\
A=150\left(1+\frac{0.08}{1}\right)^{1\cdot 13}\implies A=150(1.08)^{13}\implies A\approx 407.9435589
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