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avanturin [10]
3 years ago
10

What is the sum of the matrices shown below?

Mathematics
2 answers:
Klio2033 [76]3 years ago
8 0

Answer:

Second answer

Step-by-step explanation:

damaskus [11]3 years ago
5 0

Answer:

\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]=\left[\begin{array}{cc}9&9\\-3&2\end{array}\right]

Step-by-step explanation:

To add matrices, we add the corresponding components.

The given matrices is

\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]

We add the corresponding components to get;

\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]=\left[\begin{array}{cc}3+6&9+0\\5+-8&-2+4\end{array}\right]

We simplify to get:

\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]=\left[\begin{array}{cc}9&9\\-3&2\end{array}\right]

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Answer:

Option C) graph of line going through 1, 4 and 3, 10

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She adds 3 coins per year, then y=1+3x

At x=1, y=1+3(1)=1+3→y=4→Point=(x,y)→Point=(1,4)

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<h3>Answer:</h3>

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