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Ede4ka [16]
3 years ago
6

What is the concentration of hydronium ions after a 100ml solution of 0.02m magnesium hydroxide and 100ml of 0.05m nitric acid?

Chemistry
1 answer:
Svetllana [295]3 years ago
4 0
Mg(OH)_2 + 2HNO_3 ---\ \textgreater \   Mg(NO_3)_2 + 2H_2O

That is the balanced chemical equation.

Before reaction,
milli-moles of Mg(OH)2 = 100 x 0.02 = 2
milli-moles of HNO3 = 100 x 0.05 = 5

After reaction:
Mg(OH)2 is limiting reagent. It will react completely leaving some HNO3 behind.
milli-moles of HNO3 react = 2 x coefficient of HNO3 = 2 x 2 = 4

milli-moles of HNO3 left = 5 -4 = 1

Now, total volume = 100+ 100 = 200 mL

It is asked for hydronium ion concentration, which is basically hydrogen ion conc.
 1 HNO3 will dissociate to give 1 H+ ion.

so, milli-moles of H+ = 1 

So, concentration of H+  or hydronium(H3O+) = 1 / 200 = 0.005

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How many milliliters o a 0.2% solution o a skin test antigen must be used to prepare 4 mL o a solution containing 0.04 mg/mL o t
Klio2033 [76]

Answer:

0.08 mL

Explanation:

The solution of the skin test has a concentration of 0.2% (w/v), which means that there are 0.2 g of the antigen per 100 mL of the solution. If a new solution will be done using it, then this solution will be diluted, and the mass of the antigen added must be the same in the volume taken and at the diluted solution.

The mass is the concentration (in g/mL) multiplied by the volume of the solution (in mL), so, if m is the mass, C the concentration, V the volume, 1 the initial solution, and 2 the diluted:

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0.002*V1 = 0.00004*4

V1 = 0.08 mL

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4 years ago
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Hope it helps ya

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