Answer : The mass of nitrous oxide formed from 85.20 g of nitrogen is, 133.9 grams.
Explanation :
As we are given that, 28.01 g of nitrogen is present in 44.01 g of nitrous oxide. Now we have to determine the mass of nitrous oxide formed from 85.20 g of nitrogen.
As, 28.01 g of nitrogen is present in 44.01 g of nitrous oxide
So, 85.20 g of nitrogen is present in 
of nitrous oxide
Thus, the mass of nitrous oxide formed from 85.20 g of nitrogen is, 133.9 grams.
Answer:
![[CO]=[Cl_2]=0.01436M](https://tex.z-dn.net/?f=%5BCO%5D%3D%5BCl_2%5D%3D0.01436M)
![[COCl_2]=0.00064M](https://tex.z-dn.net/?f=%5BCOCl_2%5D%3D0.00064M)
Explanation:
Hello there!
In this case, according to the given chemical reaction at equilibrium, we can set up the equilibrium expression as follows:
![K=\frac{[CO][Cl_2]}{[COCl_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BCO%5D%5BCl_2%5D%7D%7B%5BCOCl_2%5D%7D)
Which can be written in terms of x, according to the ICE table:
Thus, we solve for x to obtain that it has a value of 0.01436 M and therefore, the concentrations at equilibrium turn out to be:
![[COCl_2]=0.015M-0.01436M=0.00064M](https://tex.z-dn.net/?f=%5BCOCl_2%5D%3D0.015M-0.01436M%3D0.00064M)
Regards!
Answer:
B
Explanation:
I had this question and got it right
54protons
77 neutrons and 2 electrons
