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3 years ago

Need help on dis plz that would be big help

Chemistry

2 answers:

Vaselesa [24]3 years ago

4 0

Answer:

Mg(OH)2

Explanation:

Magnesium hydroxide is the base since it has hydroxyl ions.

natulia [17]3 years ago

3 0

Answer:

Mg(OH)2

Explanation:

got it correct on edge 2021 :)

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2 years ago

Is cyclohexanol an alkane, alkene, or an alcohol?

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3 years ago

What is the ionic equation for the following 2FeCl(aq) 3Mg(s) 3MgCl(aq) 2Fe(s)

amid [387]

Answer : The net ionic equation will be,

$2Fe^{3+}(aq)+3Mg(s)\rightarrow 3Mg^{2+}(aq)+2Fe(s)$

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The given balanced ionic equation will be,

$2FeCl_3(aq)+3Mg(s)\rightarrow 3MgCl_2(aq)+2Fe(s)$

The ionic equation in separated aqueous solution will be,

$2Fe^{3+}(aq)+6Cl^{-}(aq)+3Mg(s)\rightarrow 3Mg^{2+}(aq)+6Cl^{-}(aq)+2Fe(s)$

In this equation, $Cl^{-}$ is the spectator ion.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$2Fe^{3+}(aq)+3Mg(s)\rightarrow 3Mg^{2+}(aq)+2Fe(s)$

7 0

3 years ago

There are several aromatic compounds with the formula C8H9Cl. Draw those that have a trisubstituted ring where the methyl groups

Kryger [21]

Answer:

$3-Chloro-1,2-dimethylbenzene$

$4-Chloro-1,2-dimethylbenzene$

Explanation:

Such types of compounds in which conjugated planer ring system and delocalized pi electrons are present are called aromatic compounds such as Toluene, Benzene and some other. Generally, these compounds follow Huckle's rule. The trisubstituted ring means a compound in which three hydrogen atoms are replaced by three other groups. In the given compound two hydrogen atoms are replaced by two methyl groups and one hydrogen atom is replaced by one Chlorine atom. From the given compound $3-Chloro-1,2-dimethylbenzene$ , and $4-Chloro-1,2-dimethylbenzene$ can be drawn.

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4 years ago

Compounds X and Y are both C7H15Cl products formed in the radical chlorination of 2,4-dimethylpentane. Base-promoted E2 eliminat

saul85 [17]

Answer:

X is 3-chloro-2,4-dimethylpentane

Explanation:

The radical chlorination of 2,4-dimethylpentane may give three products.

Based on the information that

i) both the products gives single alkene on elimination and

ii) both the products also undergoes SN2 reaction but Y reacts faster than X

We may conclude that as SN2 reaction is faster in primary alkyl halides as compared to secondary or tertiary so Y must be primary or secondary and it cannot be tertiary alkyl halide.

The possible products are shown in the figure.

The structure of X is shown in the figure.

5 0

3 years ago