The reasonable ground-state electron configuration is: 1s2 2s2 2p6 3s2 3p6 4s2 4d8
First, let us calculate the moles of solute or sodium
bicarbonate is in the 1 ml solution.
<span>moles = 1 mL * (1 g
/ 9 mL) = 0.11 moles</span>
The molar mass of sodium bicarbonate is 84 g/mol,
therefore the mass is:
mass = 0.11 moles * 84 g/mol
<span>mass = 9.33 g</span>
Na3 = 23*3 = 69
P = 31
O4 = 16*4 =64
69+ 31+ 64 = 164g/mol
0.75mol = 0.75 * 164 = 123 g
N(H₂O)=1g÷18g/mol=0,055mol
N(H₂O)=0,055mol · 6·10²³ 1/mol (Avogadro number)= 3,33·10²² molecules.
