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1 year ago

How many liters do 1.55 g of O2 occupy at STP?

Chemistry

1 answer:

den301095 [7]1 year ago

3 0

The volume that is occupied by the given mass of the oxygen gas is 1.1L

<h3>What is the volume?</h3>

We know that the volume has to do with the space that is occupied by a gas. Now we know that from the Avogadro's law, the volume that is occupied by a gas is called the molar volume of the gas and it has a value of 22.4 L.

We now have;

Number of moles of the gas = 1.55 g/32 g/mol

= 0.048 moles

If 1 mole of the gas occupies 22.4 L

0.048 moles of the gas is going to occupy 0.048 moles * 22.4 L/1 mole

= 1.1 L

Learn more about volume of a gas:brainly.com/question/24189159

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Calculate the specific heat of a piece of wood if 2000 g of wood absorbs 75,250 J of heat, and its temperature changes from 30°C

inna [77]

Answer:

Explanation:

The specific heat capacity=quantity of heat in joule/mass×change in temperature

from this question the quantity of heat is 75250,the mass is 2000 and the change in temperature is 50-30

which is 20

therefore

c=75250/2000×20

c=75250/40000

c=1.88

I hope this helps

3 0

3 years ago

Examine the given reaction. NH4NO3(s) → NH4+(aq) + NO3–(aq) ΔH° = 25.45 kJ/mol ΔS° = 108.7 J/mol·K Which of the given is correct

kobusy [5.1K]

Answer:

B)−6,942 J /mol

Explanation:

At constant temperature and pressure, you cand define the change in Gibbs free energy, ΔG, as:

ΔG = ΔH - TΔS

Where ΔH is enthalpy, T absolute temperature and ΔS change in entropy.

Replacing (25°C = 273 + 25 = 298K; 25.45kJ/mol = 25450J/mol):

ΔG = ΔH - TΔS

ΔG = 25450J/mol - 298K×108.7J/molK

ΔG = -6942.6J/mol

Right solution is:

8 0

3 years ago

A 2.36-gram sample of NaHCO3 was completely decomposed in an experiment.

enyata [817]

Answer:

Explanation:

a) The mass of the reactants is 2.36 grams, and the mass of the products is 1.57 grams plus the mass of the carbonic acid. Thus, using the law of conservation of mass, we get the mass of the carbonic acid is 2.36 - 1.57 = 0.79 grams.

b) The gram-formula mass of sodium bicarbonate is 84.006 g/mol, meaning that 2.36/84.006 = 0.028 moles were consumed. Thus, this means that in theory, 0.014 moles of carbonic acid should have been produced, which would have a mass of (0.014)(62.024)=0.868 grams. Thus, the percentage yield is (0.79)/(0.868) * 100 = 91%

8 0

2 years ago

2. A block of aluminum with a mass of 140g is cooled from 98.4oC to 62.2oC with a release of 1137J of heat. From these data, cal

NeTakaya

Q = M * C *ΔT

Q / ΔT = M

Δf - Δi = 98.4ºC - 62.2ºC = 36.2ºC

C = 1137 J / 140 * 36.2

C = 1137 / 5068

C = 0.224 J/gºC

8 0

3 years ago

What is the solubility product expression for Ag2CO3

Dominik [7]

Ksp = [Ag+]^2[CO32-]that should be it

7 0

3 years ago