a. AgBr(s)⇒ Ag⁺(aq) + Br⁻(aq)
b. Ksp AgBr = s²
c. 5 x 10⁻¹³ mol/L
<h3>Further explanation</h3>
Given
solubility AgBr = 7.07 x 10⁻⁷ mol/L
Required
The dissolution reaction
Ksp
The solubility product constant
Solution
a. dissolution reaction of AgBr
AgBr(s)⇒ Ag⁺(aq) + Br⁻(aq)
b. Ksp
Ksp AgBr = [Ag⁺] [Br⁻]
Ksp AgBr = (s) (s)
Ksp AgBr = s²
c. Ksp AgBr = (7.07 x 10⁻⁷)² = 5 x 10⁻¹³ mol/L
7.93 x 10⁶mi
Explanation:
Significant figures are numbers that shows how accurate and precise scientific measurements are reported.
Here are some rules to identifying them;
- All non-zero digits are significant
- zeros between digits are significant
- leading zero before a decimal are not significant
- trailing zero after a decimal are significant
- trailing zero before a decimal point are significant.
The number 7926381 has 7 significant numbers.
To write in the scientific notation, we simply express as N x 10ᵃ
N is the number of significant number
a is the exponent
N here is 7.93
a here is 6
7.93 x 10⁶mi
learn more:
Significant figures brainly.com/question/2746374
#learnwithBrainly
Oil has very less density as compared to water, so they never mix through. When, you put both of them in a container, then Oil floats on the surface of water
Hope this helps!
Answer: Three groups bound to it with no lone pairs
i think...
