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faltersainse [42]
2 years ago
14

How many liters do 1.55 g of O2 occupy at STP?

Chemistry
1 answer:
den301095 [7]2 years ago
3 0

The volume that is occupied by the given mass of the oxygen gas is 1.1L

<h3>What is the volume?</h3>

We know that the volume has to do with the space that is occupied by a gas. Now we know that from the Avogadro's law, the volume that is occupied by a gas is called the molar volume of the gas and it has a value of 22.4 L.

We now have;

Number of moles of the gas = 1.55 g/32 g/mol

= 0.048 moles

If 1 mole of the gas occupies 22.4 L

0.048 moles of the gas is going to occupy 0.048 moles * 22.4 L/1 mole

= 1.1 L

Learn more about volume of a gas:brainly.com/question/24189159

#SPJ1

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What is the purpose of stirring a solution while it is being heated?.
Temka [501]
Stirring and agitating chemical reactions is desirable and stirring reflux systems or any system under heating is necessary to a distribute the heat evenly throughout the system and b) to prevent splashing and boilovers.
5 0
3 years ago
Consider the chemical equation for the ionization of CH3NH2 in water. Estimate the percent ionization of CH3NH2 in a 0.050 M CH3
anyanavicka [17]

Answer:  The percent ionization of CH_3NH_2 in a 0.050 M CH_3NH_2(aq) solution is 8.9 %

Explanation:

CH_3NH_2+H_2O\rightarrow OH^-+CH_3NH_3^+

 cM                            0             0

c-c\alpha                       c\alpha            c\alpha

So dissociation constant will be:

K_b=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= concentration = 0.050 M and \alpha = degree of ionisation = ?

K_b=4.4\times 10^{-4}

Putting in the values we get:

4.4\times 10^{-4}=\frac{(0.050\times \alpha)^2}{(0.050-0.050\times \alpha)}

(\alpha)=0.089

percent ionisation =0.089\times 100=8.9\%

8 0
3 years ago
An oven heats up and the whole kitchen becomes warm because of heat transfer by
Ad libitum [116K]
B, it's properly because of convection! Please, correct me if I'm wrong :>
6 0
3 years ago
HELP
qwelly [4]

Answer:

98.4 kPa

Explanation:

Step 1: Given and required data

  • Partial pressure of water vapor at 60°C (pH₂O): 19.9 kPa (this info is tabulated)
  • Partial pressure of nitrogen (pN₂): 53.0 kPa
  • Partial pressure of helium (pHe): 25.5 kPa

Step 2: Calculate the total pressure of the gaseous mixture

The total pressure of the gaseous mixture (P) os equal to the sum of the partial pressures of the gases that form it.

P = pH₂O + pN₂ + pHe

P = 19.9 kPa + 53.0 kPa + 25.5 kPa = 98.4 kPa

8 0
3 years ago
1. Which variable is the independent variable and which is the dependent variable? Density vs. ethylene glycol
AnnyKZ [126]
<span>1. Which variable is the independent variable and which is the dependent variable? Density vs. ethylene glycol
The independent variable would be ethylene glycol and dependent variable would be density.

A. A 25-mL volumetric flask with its stopper has a mass of 32.6341 g. The same flask filled to the line with ethylene glycol (C2H6O2, automotive antifreeze) solution has a mass of 58.0091 g. What is the density of the ethylene glycol solution?

Density = 58.0091 - 32.6341 / .025 = 1015 g/L

B. What is the molarity of the ethylene glycol solution, if the mass of ethylene glycol in the solution is 12.0439 g?

Molarity = 12.0439 ( 1 mol / 62.07 g) / 0.025 = 7.8 M</span>
5 0
3 years ago
Read 2 more answers
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