All categories

1 year ago

How many liters do 1.55 g of O2 occupy at STP?

Chemistry

1 answer:

den301095 [7]1 year ago

3 0

The volume that is occupied by the given mass of the oxygen gas is 1.1L

<h3>What is the volume?</h3>

We know that the volume has to do with the space that is occupied by a gas. Now we know that from the Avogadro's law, the volume that is occupied by a gas is called the molar volume of the gas and it has a value of 22.4 L.

We now have;

Number of moles of the gas = 1.55 g/32 g/mol

= 0.048 moles

If 1 mole of the gas occupies 22.4 L

0.048 moles of the gas is going to occupy 0.048 moles * 22.4 L/1 mole

= 1.1 L

Learn more about volume of a gas:brainly.com/question/24189159

#SPJ1

You might be interested in

2. Balance the equation below, and answer the following question: What volume of chlorine gas, measured at STP, is needed to com

Juliette [100K]

Balanced equation: 2Na(s) + Cl₂(g) ---> 2NaCl(s)

when we have STP conditions, we can use this conversion: 1 mol = 22.4 L

first, we have to convert grams to molecules using the molar mass, and then use mole to mole ratio from the balanced equation.

molar mass of Na= 23.0 g/mol
ratio: 2 mol Na= 1 mol Cl₂ (based on coefficients of balanced equation)

calculations:

$6.25 g Na ( \frac{1 mol Na}{23.0 g} ) ( \frac{1 mol Cl_2}{2 mol Na} ) ( \frac{22.4 L}{1 mol} )= 3.04 L$

8 0

2 years ago

What do weather and climate have in common?

Ira Lisetskai [31]

Answer:

Explanation:

5 0

3 years ago

Read 2 more answers

100 ml is drawn from 0.1 M solution of KCl and added to 900 ml of water. What is the

grandymaker [24]

Answer:

The new concentration will be 0.01 M.

Explanation:

To determine the new concentration we use the following formula.

concentration (1) × volume (1) = concentration (2) × volume (2)

concentration (1) = 0.1 M

volume (1) = 100 mL

concentration (2) = unknown

volume (2) = 100 mL + 900 mL = 1000 mL

concentration (2) = [concentration (1) × volume (1)] / volume (2)

concentration (2) = (0.1 × 100) / 1000 = 0.01 M

3 0

2 years ago

Gas A effuses 0.68 times as fast as Gas B. If the molar mass of Gas B is 17 g, what is the mass of Gas A?

BartSMP [9]

The mass of gas A is 11.56. i got this answer by 0.68 multiplied by 17. because in this problem the key word is times.

4 0

3 years ago

The molecular weight of vitamin C , C6H8O6 is 176.12 grams over mol

IgorC [24]

Answer:

0.0250 g.

Explanation:

∵ no. of moles (n) = mass / molar mass.

<em>∴ mass of Vitamine C = (n)(molar mass)</em> = (0.000142 mol)(176.12 g/mol) = 0.02501 g = <em>0.0250 g. "three significant figures"</em>

3 0

3 years ago