Hydroxyl radicals react with and eliminate many atmospheric pollutants. However, the hydroxyl radical does not clean up everythi
ng. For example, chlorofluorocarbons, which destroy stratospheric ozone, are not attacked by the hydroxyl radical. Consider the hypothetical reaction by which the hydroxyl radical might react with a chlorofluorocarbon:
OH(g)+CF2Cl2(g)→HOF(g)+CFCl2(g)
Use bond energies to explain why this reaction is improbable. Calculate ΔHrxn of this reaction.
OH(g)+CF2Cl2(g)→HOF(g)+CFCl2(g)
Use bond energies to explain why this reaction is improbable. Calculate ΔHrxn of this reaction.
1 answer:
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Answer:- C. H
Explanations:- Reduction is gain of electron. In other words we could say that decrease in oxidation number is reduction.
As per the rules, oxidation number of hydrogen in its compounds is +1(except metal hydrides) and the oxidation number of oxygen in its compounds is -2.
The oxidation number in elemental form is zero.
In , the oxidation number of H is +1 and oxidation number of O is -2. Oxidation number of Cl in
is -1. On product side, the oxidation number of hydrogen in
is zero and in
the oxidation number of H is +1 and that of O is -2. Oxidation number of Cl in
is 0.
From above data, Oxidation number of O is -2 on both sides so it is not reduced.
Oxidation number of Cl is changing from -1 to 0 which is oxidation.
Oxidation number of H is changing from +1 to 0 which is reduction.
So, the right choice is C.H