Answer:
Hiya there!
Explanation:
ATP then binds to myosin, moving the myosin to its high-energy state, releasing the myosin head from the actin active site. ATP can then attach to myosin, which allows the cross-bridge cycle to start again; further muscle contraction can occur.
acetylcholine
: Skeletal muscle contraction and changes with exercise. (A) Neurotransmitter (acetylcholine, ACh) released from nerve endings binds to receptors (AChRs) on the muscle surface.
The muscle contraction cycle is triggered by calcium ions binding to the protein complex troponin, exposing the active-binding sites on the actin. As soon as the actin-binding sites are uncovered, the high-energy myosin head bridges the gap, forming a cross-bridge.
Credit sourced from "bio.libretexts.org"
Hope this <em><u>Helped!</u></em> :D
Answer:
74%
Explanation:
The frequency in such cases (diallelic cases) is estimated by following formula which is attached in the image:
So as per our question, the frequency of the "R allele" as per data given below will be as under:
58 red-phase (RR)
32 cross-phase (RS)
10 black/silver-phase (SS) foxes
Total plants = 58 + 32 + 10 = 100
f(R) = 58 x 2 + 32/ 2 (58+32+10)
= 116 + 32 / 200
= 148/200
= 0.74 i.e. 74%
GUANINE
Adenine always bonds with thymine, and cytosine always bonds with guanine.
hope it helps...!!!
Answer:
The question lacks options, the options are:
A) 1 out of 16
B) 3 out of 16
C) 6 out of 16
D) 9 out of 16
The answer is 1 out of 16
Explanation:
This is a DIHYBRID cross because it involves two different genes coding for distinct traits. One of the traits will be dominant while the other recessive. Hence, parents that are purebred for opposite forms of the trait means that one parent is homozygous dominant while the other is homozygous recessive. When these two parents cross, they produce F1 offsprings that all possess the dominant trait but heterozygous/hybrids.
When these hybrids are self-crossed, they produce four different combinations of gametes which when crossed using a punnet square will result in F2 offsprings with a 9:3:3:1 phenotypic ratio according to Mendel's observation.
9 represents offsprings that are dominant for both traits
The two 3's represents offsprings that are recessive for one trait and dominant for the other respectively.
1 represents offsprings that are homozygous recessive for both traits.
Hence, 1 out of 16 offsprings will be homozygous recessive for both traits.
