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Brut [27]
3 years ago
11

Hen one atom contributes both bonding electrons in a single covalent bond, the bond is called a(n) ____.

Chemistry
1 answer:
Kaylis [27]3 years ago
4 0
Hello  <span>Squirrel9177 
</span><span>

Answer: Wh</span>en one atom contributes both bonding electrons in a single covalent bond, the bond is called a coordinate covalent bond


Hope This Helps!
-Chris
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1. A container holds four times as many moles of CO2 as O2. If the total pressure in the container is 20. atm,
Hitman42 [59]

Answer:

Partial pressure of CO2 = 16 atm

Explanation:

Total number of moles of gases = 4+1 = 5 moles

Mole fraction of CO2 = 4/5

Partial pressure of CO2 = mole fraction of CO2 × total pressure

Partial pressure of CO2 = (4/5) × 20

Partial pressure of CO2 = 16 atm

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2 years ago
The soldiers are issued (infrared) goggles to help them see in the dark.
gregori [183]
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3 years ago
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Calculate the concentration imports per million ppm of DDT if a sample size of 5000 g contained 0.10 g DDT
nevsk [136]

Answer:

20ppm

Explanation:

parts per million are defined as the mass of solute in mg (In this case, mass of DDT) per kg of sample.

To solve this question we must find the mass of DDT in mg and the mass of sample in kg:

<em>Mass DDT:</em>

0.10g * (1000mg / 1g) = 100mg

<em>Mass sample:</em>

5000g * (1kg / 1000g) = 5kg

Parts per Million:

100mg / 5kg =

<h3>20ppm</h3>
3 0
3 years ago
You
Igoryamba

Answer:

The arm that was not sprayed with anything

Explanation:

The control group would be <u>the arm that was not sprayed with anything</u>.

<em>The control group during an experiment is a group that forms the baseline for comparison in other to determine the effects of a treatment. The control group does not include the variable that is being tested and as such, it provides the benchmark to measure the effects of the tested variable on the other group - the experimental group. In this case, the experimental group would be the arm that was sprayed with the repellent.</em>

8 0
3 years ago
What is 2.75 mol of O2
ANTONII [103]

Answer:

2,75 mol of O2 it's 88 g of O2.

Explanation:

The weight of the diatomic molecule O2 is 32 g/mol. So considering that, you should multiply 2,75 mol · 32 = 88g :)

3 0
2 years ago
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