Answer:
V1 = 3.09 L
Explanation:
Initial Pressure, P1 = 15.6 psi
Initial Volume, V1 = ?
Final Pressure, P2 = 25.43 psi
Final Volume, V2 = 1.895 L
The relationship between these quantities is given by boyles law;
V1P1 = V2P2
V1 = V2P2 / P1 = 1.895 * 25.43 / 15.6
V1 = 3.09 L
150 g SO₂ = 2.36 mol SO₂
M_r = 32.06 + 2×16.00 = 32.07 + 32.00 = 64.06
Moles of SO₂ = 151 g SO₂ × [1 mol SO₂/64.06 g SO₂] = 2.36 mol SO₂
Answer:
-0.93 °C
Explanation:
Hello,
The freezing-point depression is given by:
Whereas 
is the freezing temperature of the solution, 
is the freezing temperature of the pure solvent (0 °C since it is water), 
the Van't Hoff factor (1 since the solute is covalent), 
the solvent's freezing point depression point constant (in this case 
) and 
the molality of the glucose.
As long as the unknown is , solving for it:
Best regards.
Answer:
The concentration of the acid is about 0.114 M (option E)
Explanation:
Step 1: Data given
Volume of the monoprotic acid = 25.0 mL = 0.025 L
Molarity of the monoprotic acid = ?
Molarity of the NaOH solution = 0.115 M
Volume NaOH = 24.8 mL = 0.0248 L
Step 2: Calculate the concentration
a*Cb * Vb = b * Ca * Va
⇒ a = the coeficient of NaOH = 1
⇒ Cb = the molarity of the acid = TO BE DETERMINED
⇒ Vb = the volume of the acid = 0.025 L
⇒ b = the coefficient of the acid = monoprotic = 1
⇒ Ca = the moalrity of NaOH = 0.115 M
⇒ Va = the volume of NaOH = 0.0248 L
1 * Cb * 0.025 = 1 * 0.115 * 0.0248
0.025 Cb = 0.002852
Cb = 0.11408 M
The concentration of the acid is about 0.114 M
