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Softa [21]
3 years ago
8

Oxygen has 8 plus-charged protons. The number of minus-charged electrons is

Chemistry
1 answer:
DiKsa [7]3 years ago
6 0

A single oxygen has atomic number 8 that means the nuclei of all oxygen atoms have eight protons. The number of minus-charged electron is two but the number of electrons is 10. <span>To gain a minus two-charge ion, it must have two more negative electrons than positive charged protons. With this, the ion has 10 electrons, which give it a -2 net charge. </span>

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A compound has the following percentage composition: 40.0% carbon, 6.72% hydrogen, 53.28% oxygen. What is the amount of carbon m
Vadim26 [7]

Answer:

So we're trying to find the number of carbon moles in the compound. We know that we have 200g of the compound and that 40% of it is Carbon. and 40% of 200 is 80g (change 40% into a decimal and multiply it by 200 and you get 80g)

So 80g of the compound is carbon. In order to find the moles of Carbon, I have to divide the mass by the molar mass of the element.

We know from our periodic table that the molar mass for carbon is 12g/mol

\frac{80}{12} = 6.67\ mol

<u>Therefore we have 6.67 moles of carbon in the compound</u>

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2 years ago
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Which of the following best describes a solution?
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Answer:

homogeneous mixture

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3 years ago
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What can be concluded about the purpose many robots will have in the future
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Answer:

Robots will be created to allow scientists to use computer programs.

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3 years ago
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Convert the following numbers of calories or
muminat

Answer:

a. joules=32823480 , kilojoules=32823.48

b. joules=1979868.8 , kilojoules=1979.8688

c. joules=260002.128 , kilojoules=260.002128

d. joules=180012416 , kilojoules=180012.416

Explanation:

calories to kilo joules=multiply the energy value by 4.184

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7 0
3 years ago
Balance each of the following examples of heterogeneous equilibria and write each Kc expression. Then calculate the value of Kc
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Explanation:

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Kc=\frac{[Na[Al(OH)_4]]^2*[H_2]^7}{[NaOH]^2}

The Kc for the reverse reaction is the inverse of the Kc of the reaction:

Kc_{reverse}=\frac{1}{Kc}=\frac{1}{11}=0.091

2) H_2O(l) + SO_3(g) \longleftrightarrow H_2SO_4 (aq)

Kc=\frac{[H_2SO_4]}{[SO_3]^2}

The Kc for the reverse reaction is the inverse of the Kc of the reaction:

Kc_{reverse}=\frac{1}{Kc}=\frac{1}{0.0123}=81.3

3)  P_4(s) + 3 O_2(g) \longleftrightarrow P_4O_6(s)

Kc=\frac{1}{[O_2]^3}

The Kc for the reverse reaction is the inverse of the Kc of the reaction:

Kc_{reverse}=\frac{1}{Kc}=\frac{1}{1.56}=0.641

5 0
4 years ago
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