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vichka [17]
3 years ago
9

The​ school's computer lab goes through 3 reams of printer paper every 2 weeks. Find out how long 5 cases of printer paper is li

kely to last​ (a case of paper holds 8 reams of​ paper). The 5 cases will last nothing weeks. ​(Round to the nearest whole number as​ needed.)  
Mathematics
1 answer:
vovikov84 [41]3 years ago
8 0

Answer:

26 weeks

Step-by-step explanation:

If you consider one case of paper then it has 8 reams.

So, if there are 5 cases of printer paper, then it will be equivalent to (5×8) =40 reams of paper.

Now, it is given that within 2 weeks in the school's computer lab 3 reams of printer paper are used.

Therefore, 40 reams i.e. 5 cases of paper will be used in (\frac{2*40}{3}) = 26.67 weeks ≈26 weeks. (Answer)

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You travel from point A to point B in a car moving at a constant speed of 70 km/h. Then you travel the same distance from point
tankabanditka [31]

Answer:

Yes, the average speed for the entire trip from A to C is equal to 80\frac{km}{h}

Step-by-step explanation:

The average speed of an object is defined as the distance traveled divided by the time elapsed. Velocity is a vector quantity, and average velocity can be defined as the displacement divided by the time. For the special case of straight line motion in the x direction, the average velocity takes the form:

V_a_v_e_r_a_g_e=\frac{x_2-x_1}{t_2-t_1}=\frac{Δx}{Δt}

If the beginning and ending velocities for the motion are known, and the acceleration is constant, the average velocity can also be expressed as:

V_a_v_e_r_a_g_e=\frac{V_1+V_2}{2}

We Know that:

V_1=70\frac{km}{h} \\\\V_2=90\frac{km}{h}

Replacing the values:

V_a_v_e_r_a_g_e=\frac{70+90}{2} =\frac{160}{2}=80\frac{km}{h}

5 0
3 years ago
A bouquet of lilies and tulips has 20 flowers.
motikmotik

Answer:8 lilies and 12 tulips; total of 20 flowers.

Step-by-step explanation:

8 lilies for $3 each equals $24. 12 tulips for $2 each equals $24. Add that together and the total for the bouquet is $48.

4 0
3 years ago
For problems 29 - 31 the graph of a quadratic function y=ax^2 + bx + c is shown. Tell whether the discriminant of ax^2 + bx + c
Elan Coil [88]

Answer:

29) discriminant  is positive

30) discriminant  is 0

31) discriminant  is negative

Step-by-step explanation:

the graph of a quadratic function y=ax^2 + bx + c is shown. Tell whether the discriminant of ax^2 + bx + c = 0 is positive, negative, or zero.

In the graph of question number 29 we can see that the graph intersects the x axis at two points

so the equation has 2 solutions.

When the equation has two solution then the discriminant is positive

In the graph of question number 30 we can see that the graph intersects the x axis at only one point

so the equation has only  1 solution.

When the equation has only one solution then the discriminant is equal to 0

In the graph of question number 30 we can see that the graph does not intersects the x axis  

so the equation has 2 imaginary solutions.

When the equation has two imaginary solutions then the discriminant is negative

3 0
4 years ago
To the nearest hundredth, how many cm are in 47 in? (1 in = 2.54 cm)
4vir4ik [10]
Easy. If 1 In. = 2.54 Cm. then the equation would be 47 * 2.54 = 119.38.
5 0
3 years ago
Read 2 more answers
Select the statements that are true for the graph of y=(x+2)^2+4
likoan [24]
Alrigty

in form
y=a(x-h)^2+k
the vertex is (h,k)
the constant, a, deterimines the size and direction
if a>0, then the parabola opens up and the vertex is the minimum
if a<0 then the parabola opens down and the vertex is the maximum

so we are given
y=1(x-(-2))^2+4
1>0 so it opens up
vertex is (-2,4)
the vertex is a minimum


the vertex is (-2,4) and the graph has a minimum
3 0
3 years ago
Read 2 more answers
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