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2 years ago

Factor 13x2 + 13x + 9x + 9 = 0

Mathematics

1 answer:

Alex787 [66]2 years ago

8 0

Answer:

$\Large \boxed{x=\frac{-9}{13} \ \ \mathrm{or} \ \ x = -1}}$

Step-by-step explanation:

$13x^2 + 13x + 9x + 9 = 0$

Factor the expression.

$13x(x+1)+9(x+1)=0$

Take (x + 1) as a common factor.

$(13x+9)(x+1)=0$

Set factors equal to 0.

First possibility:

$13x + 9 = 0$

$13x=-9$

$\displaystyle x=\frac{-9}{13}$

Second possibility:

$x+1=0$

$x=-1$

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The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .

In the question ,

it is given that ,

the probability of committing at least , type I error is = 0.7

we have to find the number of tests ,

let the number of test be n ,

the above mentioned situation can be written as

1 - P(no type I error is committed) ≥ P(at least type I error is committed)

which is written as ,

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2 years ago

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2 years ago

Read 2 more answers

How do I solve this????

Arlecino [84]

Let's say the numbers are "a" and "b"
hmm say "a" is the smaller, and "b" the greater

so "b" is "4 more than 5 times" "a"

so... 5 times "a" is 5*a or 5a
4 more than "that", will be "that" + 4
or
5a + 4

so.. whatever "a" is, "b" is 5a+4

now, their sum is 22, as opposed to "zz" hehe

so $\bf \begin{cases}
a+b=22\\
--------------\\
\boxed{b}=5a+4\qquad thus\\
--------------\\
a+\boxed{5a+4}=22
\end{cases}$

solve for "a", to see what the smaller one is

what's "b"? well, b = 5a + 4

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2 years ago

A club is choosing 2 members to serve on a committee. The club has nominated 2 women and 4 men. Based on chance alone, what is t

tekilochka [14]

Answer:

53.33% probability that one woman and one man will be chosen to be on the committee

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the members are chosen is not important, so we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

What is the probability that one woman and one man will be chosen to be on the committee?

Desired outcomes:

One woman, from a set of 2, and one man, from a set of 4. So

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Total outcomes:

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Probability:

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53.33% probability that one woman and one man will be chosen to be on the committee

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2 years ago

Factor 13x2 + 13x + 9x + 9 = 0​

Factor 13x2 + 13x + 9x + 9 = 0