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Elodia [21]
3 years ago
14

Factor 13x2 + 13x + 9x + 9 = 0​

Mathematics
1 answer:
Alex787 [66]3 years ago
8 0

Answer:

\Large \boxed{x=\frac{-9}{13} \ \ \mathrm{or} \ \ x = -1}}

Step-by-step explanation:

13x^2  + 13x + 9x + 9 = 0

Factor the expression.

13x(x+1)+9(x+1)=0

Take (x + 1) as a common factor.

(13x+9)(x+1)=0

Set factors equal to 0.

First possibility:

13x + 9 = 0

13x=-9

\displaystyle x=\frac{-9}{13}

Second possibility:

x+1=0

x=-1

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Given logx 2=p and logx 7=q , express log7 4x³ in terms of p and q.​
Ksju [112]

Answer: (2*p + 3)/q

Step-by-step explanation:

First, let's remember the relationships:

Logₙ(a) = Ln(a)/Ln(n)

Ln(A*B) = Ln(A) + Ln(B)

Ln(a^n) = n*Ln(a)

Now, we know that:

Logₓ(2) = p

Logₓ(7) = q

We want to express:

Log₇(4*x^3) in terms of p and q.

First, we can rewrite the first two relations as:

Ln(2)/Ln(x) = p

Ln(7)/ln(x) = q

then we have:

Ln(2) = p*Ln(x)

Ln(7) = q*Ln(x)

Ok:

Now let's play with our equation:

Log₇(4*x^3)

First, this is equal to:

Ln(4*x^3)/Ln(7)

We now can rewrite this as:

(Ln(4) + Ln(x^3))/Ln(7)

= (Ln(2^2) + Ln(x^3))/Ln(7)

= (2*Ln(2) + 3*Ln(x))/Ln(7)

Now we can replace Ln(2) by p*Ln(x) and Ln(7) by q*Ln(x)

(2*p*Ln(x) + 3*Ln(x))/(q*Ln(x)) = (2*p + 3)/q

This is the expression we wanted.

8 0
3 years ago
Which of the following is the inverse function of y = 3x + 1?
Shalnov [3]
Y= (x-1) /3 is the correct answer
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2 years ago
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A number n, is multiplied by -0.7 the product is -1/2 what is the value of n
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I’m assuming that -0.7 was multiplied with -1/2
7 0
2 years ago
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MAXImum [283]
4. B is the answer
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7 0
3 years ago
What is the value of log279?<br> -3/2, -2/3, 2/3, 3/2
kaheart [24]

Answer:

2/3

Step-by-step explanation:

log27(9)

Factor the number: 27=3³

= log3³(9)

Apply log rule: loga^b(x) - 1/b loga(x).

log3³(9) =1/3 log3³(9)

=1/3 log3³(9)

Factor the number: 9=3²

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Apply log rule: loga(a^b) =b

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3 0
2 years ago
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