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Sergeeva-Olga [200]
3 years ago
7

Find the real number root

Mathematics
2 answers:
Nataliya [291]3 years ago
5 0
<h2><u>Answer </u></h2>

No real number root

<h3><u>Method</u></h3>There is no real number root because it is a negative number
noname [10]3 years ago
4 0

Answer:

There is no real number root

Step-by-step explanation:

There is no real number root because there is a negative number inside the root.

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Use implicit differentiation to find the negative slope of a tangent to the circle x^2+y^2=16 at x=-2
SVETLANKA909090 [29]

Answer:

slope = - \frac{\sqrt{3} }{3}

Step-by-step explanation:

Differentiating implicitly with respect to x

2x + 2y \frac{dy}{dx} = 0

2y \frac{dy}{dx} = - 2x

\frac{dy}{dx} = - \frac{2x}{2y} = - \frac{x}{y}

\frac{dy}{dx} is the measure of the slope of the tangent

rearrange equation to find corresponding y-coordinate of x = - 2

y² = 16 - 4 = 12 = 2\sqrt{3} ⇒ y = ± 2\sqrt{3}

using x = - 2, y = - 2\sqrt{3}, then

\frac{dy}{dx} = - \frac{1}{\sqrt{3} } = - \frac{\sqrt{3} }{3}


3 0
3 years ago
What is 2/3 × 1/5what does this equal ​
Tom [10]
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6 0
3 years ago
How much is 11+5+3x2+8x1?
adoni [48]
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8 0
3 years ago
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Identify each matrix A such that A^2 has identical diagonal elements?
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Matrix:

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3 years ago
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