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EastWind [94]
2 years ago
8

What does the photoelectric effect prove?

Chemistry
1 answer:
Elza [17]2 years ago
6 0

Answer:

<em>By showing that changing the frequency of light causes the emission of faster electrons. </em>

Explanation:

<em>The photoelectric effect happens when light strikes a metal surface causing the emission of electrons from it (photoelectrons). </em>

<em>If you increase the intensity of the light you get, as acresult, more electrons emitted but their kinetic energy does not increase. </em>

<em>If you increase the frequency of the incident light the number of photoelectrons emitted does not increase while the velocity, and so their kinetic energy, increases...the emitted electrons are more...energetic! </em>

<em> </em>

<em>This can be explained considering the incident light as a shower of particle-like packets of energy (photons); if you increase the intensity you simply increase the number of packets (all with the same energy) hitting the metal; these can be used by a lot of electrons to escape. </em>

<em>On the other hand if you increase the frequency the number of packets remains the same (emitting fewer electrons perhaps) but the energy carried by each of them increases. </em>

<em>Each packet carries an energy directly proportional to the frequency.</em>

<em />

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ki77a [65]

Answer:

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Explanation:

First, we need to write the half-reactions:

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XeO₃ →  Xe Reduction

To balance the reduction in acidic aqueous solution we need to add waters in the other side of the reaction as oxygens are present:

XeO₃ →  Xe + 3H₂O

And H⁺ as hydrogens from water we have:

XeO₃ + 6H⁺ →  Xe + 3H₂O

To balance the charge:

<h3>XeO₃ + 6H⁺ + 6e⁻ →  Xe + 3H₂O  Reduction -Balanced-</h3><h3 />

To cancel out the electrons of both half-reaction we need to multiply oxidation 3 times:

6Br⁻ → 3Br₂ + 6e⁻

XeO₃ + 6H⁺ + 6e⁻ →  Xe + 3H₂O  

And the balanced reaction in acidic aqueous solution is the sum of both half-reactions:

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5 0
3 years ago
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