Answer:
I = 1.23 A
Explanation:
Given that,
The resistance of the lightbulb, R = 96.8 Ω
Voltage, V = 120 V
We need to find the current flows through the lightbulb. Let the current be I. We can use the ohm's law to find it i.e.
So, the current flows through the bulb is 1.23 A.
The reaction that has been, following the law of conservation of mass has been .
The law of conservation has been given in the chemical reaction that there has been no loss or gain of the mass and energy.
The law of conservation has been evident when there has been an equal number of atoms of each element on the product and the reactant side.
<h3 /><h3>Conservation of mass in Cellular respiration</h3>
The following reactions have been identified as:
Carbon atoms
Reactant = 3
Product = 18
Oxygen atoms
Reactant = 9
Product = 18
Hydrogen atoms
Reactant = 6
Product = 36
The number of atoms is not equal on the product and reactant side, thus not follows the law of conservation of mass.
Carbon atoms
Reactant = 6
Product = 6
Oxygen atoms
Reactant = 24
Product = 18
Hydrogen atoms
Reactant = 12
Product = 12
The number of atoms is not equal on the product and reactant side, thus not follows the law of conservation of mass.
Carbon atoms
Reactant = 6
Product = 6
Oxygen atoms
Reactant = 18
Product = 18
Hydrogen atoms
Reactant = 12
Product = 12
The number of atoms is equal on the product and reactant side, thus follows the law of conservation of mass.
Carbon atoms
Reactant = 6
Product = 0
Oxygen atoms
Reactant = 12
Product = 12
Hydrogen atoms
Reactant = 24
Product = 0
The number of atoms is not equal on the product and reactant side, thus not follows the law of conservation of mass.
Thus, the reaction that has been following the law of conservation of mass has been .
Learn more about law of conservation, here:
The relative molecular mass of acid A : 50 g/mol
<h3>Further explanation</h3>Given
40.0 cm³(40 ml) of 0.2M sodium hydroxide
0.2g of a dibasic acid
Required
the relative molecular mass of acid A
Solution
Titration formula
M₁V₁n₁=M₂V₂n₂
n=acid/base valence(number of H⁺/OH⁻)
NaOH ⇒ n = 1
Dibasic acid = diprotic acid (such as H₂SO₄)⇒ n = 2
mol = M x V
Input the value in the formula :(1 = NaOH, 2=dibasic acid)
0.2 x 40 x 1 = M₂ x V₂ x 2
M₂ x V₂ = 4 mlmol = 4.10⁻³ mol ⇒ mol of Acid A
The relative molecular mass of acid A (M) :