the answer is actually 118 look it up
Answer:
I think so henterogeneous
We know,
AgNO3 + NaCl ⇒ NaNO3 + AgCl(s)
The moles of Na+ present:
0.5 L * 0.001 mol/L
= 5 x 10⁻⁴ mol
Moles of Ag+ present:
0.5 * 0.02
= 0.01 mol
The limiting reactant is Na
Therefore, the moles of Ag reacted:
5 x 10⁻⁴
AgCl is insoluble in water; therefore, the AgCl formed will precipitate
Answer:
0.84kg of gatorade powder is needed.
Explanation:
From the question given above, we were told that the team manager mixes 0.6kg of gatorade powder with 5 gallons of water.
Now, to obtain the desired amount of the powder of gatorade needed for 7 gallons of water, we simply do the following:
If 0.6kg of gatorade powder required 5 gallons of water,
Then Xg of gatorade will require 7 gallons of water i.e
Xg of gatorade = (0.6 x 7)/5
Xg of gatorade = 0.84kg
Therefore, to maintain the same gatorade mixture, the team manager must mix 0.84kg of gatorade powder with the 7 gallons of water.
