Question

A particle A of mass 2kg originally moving with a velocity of 3ms collides directly with another particles B of mass 2kg moving with a velocity of 2ms in the opposite direction so that the velocity of A become 1ms after impact . Find the velocity of B after the impact.​

Answer 1

Answer:

- 1 m/s ( here (-) means the opposite direction of A)

Explanation:

Let m1=2kg, m2=2kg,u1= 3m/s,u2= -2 m/s, v1= 1m/s

m1u1+m2u2= m1v1+m2v2

2×3+2×(-2) = 2×1 + 2x

2= 2(1+x)

x = -1

Hope it helps