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Evgesh-ka [11]
3 years ago
7

A particle A of mass 2kg originally moving with a velocity of 3ms collides directly with another particles B of mass 2kg moving

with a velocity of 2ms in the opposite direction so that the velocity of A become 1ms after impact . Find the velocity of B after the impact.​
Physics
1 answer:
leonid [27]3 years ago
7 0

Answer:

- 1 m/s ( here (-) means the opposite direction of A)

Explanation:

Let m1=2kg, m2=2kg,u1= 3m/s,u2= -2 m/s, v1= 1m/s

m1u1+m2u2= m1v1+m2v2

2×3+2×(-2) = 2×1 + 2x

2= 2(1+x)

x = -1

Hope it helps

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When resting, a person has a metabolic rate of about 3.0 105 joules per hour. The person is submerged neck-deep into a tub conta
jek_recluse [69]

Answer:

The temperature after half an hour is 19.3002^{\circ}

Solution:

As per the question;

Metabolic rate of the person is 3.0105 J/h

Temperature, T = 19.30^{\circ}

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Time duration, t = 0.5 h = 30 min = 180 s

Now,

Heat, Q = ms\Delta t

Thus heat transfer in half an hour:

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Now, the temperature of water after half an hour, T' is given by:

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where

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T' = 19.3002 ^{\circ}

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3 years ago
Speed has what properties?
BlackZzzverrR [31]

Answer:

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7 0
2 years ago
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Stan is driving north on his scooter at 8m/s, accelerates 11m/s (North) in 4s, drives a constant velocity for the next 15s, and
kow [346]

A) Acceleration: a_1 = 0.75 m/s^2, a_2 = 0, a_3 = -1.57 m/s^2

B) The total displacement is 209.5 m north

C) The average velocity is 8.06 m/s north

Explanation:

A)

Acceleration is defined as:

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time taken for the velocity to change from u to v

Here we have:

- In the first  segment,

u = 8 m/s north

v = 11 m/s north

t = 4 s

So the acceleration is

a_1 = \frac{11-8}{4}=0.75 m/s^2 (north)

- In the second segment, Stan drives at a constant velocity: so the final velocity is equal to the initial velocity,

u = v

Therefore, the acceleration is zero: a_2 = 0

- In the third segment,

u = 11 m/s (north)

v = 0 (he comes to a stop)

t = 7 s

So the acceleration is

a=\frac{0-11}{7}=-1.57 m/s^2

And the negative sign means the acceleration is south, opposite to the direction of motion.

B)

In a uniformly accelerated motion, the displacement can be calculated as:

s=ut+\frac{1}{2}at^2

where

u is the initial velocity

a is the acceleration

t is the time

- For the first segment, we have

u = 0\\a = 0.75 m/s^2\\t=4 s

So the displacement is

s_1 = 0+\frac{1}{2}(0.75)(4)^2=6 m

- For the second segment, we have

u = 11 m/s\\a = 0\\t=15 s

So the displacement is

s_2 = (11)(15)+0=165 m

- For the third segment, we have

u = 11\\a = -1.57 m/s^2\\t=7 s

So the displacement is

s_3 = (11)(7)+\frac{1}{2}(-1.57)(7)^2=38.5 m

So the total displacement is:

s = 6 m + 165 m + 38.5 m = 209.5 m

In the north direction (positive direction)

C)

The average velocity is given by:

v=\frac{d}{t}

where

d is the total displacement

t is the total time

Here we have:

d = 209.5 m

t = 26 s

Therefore, the average velocity is

v=\frac{209.5}{26}=8.06 m/s (north)

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

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#LearnwithBrainly

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