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Vikki [24]
3 years ago
13

If a gasoline engine has an efficiency of 21 percent and losses 780 J to the cooling system and exhaust during each cycle, how m

uch work is done by the engine?
Physics
1 answer:
NISA [10]3 years ago
7 0

As we know that efficiency of engine is given as

efficiency = \frac{W}{Q_i}

also we know that

Q_i - Q_o = W

given that

Q_o = 780 J

efficiency = 21%

now we have

0.21 = \frac{Q_i - Q_o}{Q_i}

0.21 Q_i = Q_i - 780

0.79Q_i = 780

Q_i =987.3J

now we have

W = 987.3 - 780 = 207.3 J

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Answer:

1.5 m

Explanation:

Let the distance from the box to the pivot be c.

Let the distance from the pivot to the effort be y.

From the question given above, the following data were obtained:

Effort force (Fₑ) = 7 N

Force of resistance (Fᵣ) = 14 N

Distance from the box to the pivot (c) = 0.75 m

Distance from the pivot to the effort (y) =?

Clockwise moment = Fₑ × y

Anticlock wise moment = Fᵣ × c

Clockwise moment = Anticlock wise moment

Fₑ × y = Fᵣ × c

7 × y = 14 × 0.75

7 × y = 10.5

Divide both side by 7

y = 10.5 / 7

y = 1.5 m

Therefore, the distance from the pivot to the effort is 1.5 m

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The meter out circuit is the flow control circuit design that can most effectively control an overrunning load.

The meter-out circuit can be very accurate, but are not efficient. The meter-out circuit can control overrunning as well as opposing loads while the other one method must be used with opposing loads only. The choice of flown control valve method and the location of the flow control in the circuit are dependent on the type of application being controlled.

<h3>What is a Circuit ?</h3>

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Hence, flow control circuit design that can best control an overrunning load is the opposing circuit

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Reil [10]

Answer:

15.6 C

Explanation:

Here we are given a temperature in Fahrenheit (F). We want to convert it into Celsius degrees (C).

The conversion can be done by using the following equation:

T(C)=\frac{5}{9}(T(F)-32)

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In this problem, we have

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Therefore, by applying the equation,

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