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ozzi
3 years ago
8

A fluid flows through a pipe of constant circular cross-section diameter 1.1m with a mean velocity of 50cm/s. The mass flow rate

of the flow through the pipe, given by the formula mass flow rate = (density) (mean velocity) (cross - sectional area), is measured to be 110 kg/s. Find the specific gravity, specific weight and specific volume of the fluid.
Engineering
1 answer:
allochka39001 [22]3 years ago
3 0

Answer:

Explanation:

Given

diameter(d)=1.1 m

mean velocity(u)=50 cm/s

mass flow rate(m)=110 kg/s

A=0.950 m^2

m=\rho \cdot A\cdot u

where \rho =density of fluid

110=\rho \times 0.95\times 0.5

\rho =231.46 kg/m^3

Therefore specific gravity=\frac{\rho }{\rho _{water}}

=\frac{231.46}{1000}=0.231

Specific weight=\rho \cdot g=231.46\times 9.81=2270.70 kg/m^2-s^2

specific volume=\frac{1}{density}

=\frac{1}{231.46}=0.00432 m^3/kg

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