1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Hunter-Best [27]
3 years ago
7

A process consists of two steps: (1) One mole of air at T = 800 K and P = 4 bar is cooled at constant volume to T = 350 K. (2) T

he air is then heated at constant pressure until its temperature reaches 800 K. If this two-step process is replaced by a single isothermal expansion of the air from 800 K and 4 bar to some final pressure P, what is the value of P that makes the work of the two processes the same? Assume mechanical reversibility and treat air as an ideal gas with CP = (7/2)R and CV = (5/2)R.
Engineering
1 answer:
mihalych1998 [28]3 years ago
5 0

Answer:

2.279 bar

Explanation:

I will be using R = 8.314*10^{-2} \frac{l*bar}{K*mol} here.

Also, you should know that 1 l*bar = 0.1 kJ

Lastly, the definition of work for <em>any</em> thermodynamics process:

W=-\int P \, dV                                                           eq1        

So, getting started. We will first find the work for the first process

  • The first step, we have a constant volume process, therefore, there is no work done (W = 0) You can see it from this integral

-\int\limits^{V_2} _{V_1} {P} \, dV

There is no volume change, so no work can be done

  • In the second step We now have a constant pressure process. Don't worry, our eq1 still works here. Take in mind now that P is now a function of T. And since we are assuming that air is an ideal gas, we can use Ideal gas law PV = nRT here. So:

T = \frac{PV}{nR}

But there is no T in this integral!

W=-\int P \, dV

This is where we will do a little calculus trick.

In differential form:

dT=d\frac{PV}{R}

Note that P and R is constant So...

dT=\frac{P}{R}dV

Now we can substitute dV in the integral with dT

-\int\limits^{T_2} _{T_1} {\frac{PR}{P}} \, dT

And we get

W = -\int\limits^{T_2} _{T_1} {\frac{PR}{P}} \, dT

W = -3.741\ kJ

So, in total, the work <em>done</em><em> </em>by this process is 3.741 kJ. Make sure you do not confuse the sign of your answer. It is always good to state <em>prior</em> to your calculation which sign, + or - , will be assigned to work done <em>by </em>your system or work done <em>to</em> your system.

Now for the second process

  • We have an isothermal process, which means that T is constant during the process. So, similar to part 2 of the first process, by using ideal gas law:

P=\frac{RT}{V}

Which we will substitute into our ever reliable eq1

W=-\int\limits^{V_2} _{V_1} {\frac{RT}{V}} \, dV

Solving this integral, we get

W= -RT(ln(V_2)-ln(V_1))=-RTln(\frac{V_2}{V_1})                            eq2

Now, since we don't know V but we know P, We can simply use Ideal gas law(again)

V=\frac{RT}{P}

And substitute it in eq2, so:

W= -RTln(\frac{P_1}{P_2}=-RT(ln(P_1)-ln(P_2))

In kJ unit

W=-0.1*800*0.08314*(ln(4)-ln(P_2))

  • Finally, we find P_2 of process 2 that would make that work done by both process equal. So, we equate the work done by both process

W=-3.741 =-0.1*800*0.08314(ln(4)-ln(P_2))

Solve this equation for P_{2} and we get

P_{2}=2.279\ bar

You might be interested in
Set up the following characteristic equations in the form suited to Evanss root-locus method. Give L(s), a(s), and b(s) and the
Sunny_sXe [5.5K]

Answer:

attached below is the detailed solution and answers

Explanation:

Attached below is the detailed solution

C(iii) : versus the parameter C

The parameter C is centered in a nonlinear equation, therefore the standard locus will not apply hence when you use a polynomial solver the roots gotten would be plotted against C

4 0
3 years ago
What is the focus of 7th grade civics
Jobisdone [24]
C. seems like the best answer. i may be wrong so don’t quote me on that
7 0
3 years ago
Read 2 more answers
Meaning of temporary stitches​
algol13

Answer:

They are use to hold garment or fabric pieces together before pernament stitches are made

6 0
2 years ago
Read 2 more answers
Which of the following is NOT a breach of Netiquette?
alexandr402 [8]

Answer:

I need some more point and i do not understand your question

Explanation:

7 0
3 years ago
Consider a 2-shell-passes and 8-tube-passes shell-and-tube heat exchanger. What is the primary reason for using many tube passes
Maru [420]

Answer:

See explanation

Explanation:

Solution:-

- The shell and tube heat exchanger are designated by the order of tube and shell passes.

- A single tube pass: The fluid enters from inlet, exchange of heat, the fluid exits.

- A multiple tube pass: The fluid enters from inlet, exchange of heat, U bend of the fluid, exchange of heat, .... ( nth order of pass ), and then exits.

- By increasing the number of passes we have increased the "retention time" of a specific volume of tube fluid; hence, providing sufficient time for the fluid to exchange heat with the shell fluid.

- By making more U-turns we are allowing greater length for the fluid flow to develop with " constriction and turns " into turbulence. This turbulence usually at the final passes allows mixing of fluid and increases the heat transfer coefficient by:

                                U ∝ v^( 0.8 )    .... ( turbulence )

- The higher the velocity of the fluids the greater the heat transfer coefficient. The increase in the heat transfer coefficient will allow less heat energy carried by either of the fluids to be wasted ; hence, reduced losses.

Thereby, increases the thermal efficiency of the heat exchanger ( higher NTU units ).

5 0
3 years ago
Other questions:
  • A device is needed to accelerate a 3000 lb vehicle into a barrier with constant velocity to test its 5 mph bumpers. The vehicle
    12·2 answers
  • How does a carburetor work?
    7·1 answer
  • HELP<br><br><br>the overall width of a part is dimensioned as 3.00 ± 0.02. what is the tolerance
    14·2 answers
  • A steel bar 100 mm long and having a square cross section 20 mm x 20 mm is pulled in
    6·1 answer
  • 3.24 Program: Drawing a half arrow (Java) This program outputs a downwards facing arrow composed of a rectangle and a right tria
    12·1 answer
  • Some chemical reaction is being run inside a sealed gas cylinder. During the reaction, a gaseous product is formed. The pressure
    14·1 answer
  • Which scientist was famous for his laws on gravity?
    10·2 answers
  • When do you need to apply for program completion and review?
    11·1 answer
  • A force measuring instrument comes with a certificate of calibration that identifies two instrument errors and assigns each an u
    12·1 answer
  • A sprinter reaches his maximum speed in 2.5sec from rest with constant acceleration. He then maintains that speed and finishes t
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!