Question

Evaluate 2 sin 60° + tan 45° + cos²60°​

Answer 1

Answer:

$\boxed{\sf 2sin \: 60 ^{ \circ} + tan \: 45^{ \circ} + {cos}^{2} \ 60^{\circ} = 2.98}$

Step-by-step explanation:

We know:

$\sf sin \: 60 ^{ \circ} = \frac{ \sqrt{3} }{2} \\ \\ \sf tan \: 45 ^{ \circ} = 1 \\ \\ \sf cos \: 60 ^{ \circ} = \frac{1}{2}$

So,

$\sf \implies 2sin \: 60 ^{ \circ} + tan \: 45^{ \circ} + {cos}^{2} \: 60^{ \circ} \\ \\ \sf \implies \cancel{2} \times \frac{ \sqrt{3} }{ \cancel{2}} + 1 + {( \frac{1}{2}) }^{2} \\ \\ \sf \implies \sqrt{3} + 1 + {( \frac{1}{2}) }^{2} \\ \\ \sf \implies \sqrt{3} + 1 + \frac{1}{4} \\ \\ \sf \implies \sqrt{3} + 1 + 0.25 \\ \\ \sf \implies 1.25 + \sqrt{3} \\ \\ \sf \implies 1.25 + 1.73 \\ \\ \sf \implies 2.98$

Answer 2

Answer:

1.25+√3 or 2.9821 to the nearest ten thousandth.

Step-by-step explanation:

sin 60 = √3/2,  tan 45 = 1 and cos^2 60 = (1/2)^2 = 1/4

So we get 2 *√3/2 + 1 + 1/4

= √3 +  1.25