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4 years ago

12

Two conductors are made of the same material and have the same length. conductor a is a solid wire of diameter 1.3 mm. conductor

b is a hollow tube of outside diameter 8.0 mm and inside diameter 7.0 mm. what is the resistance ratio ra/rb , measured between their ends?

1 answer:

max2010maxim [7]4 years ago

4 0

I think the answer is 3

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A train travels 55km, south along a straight track in 34minutes. What is the train Ls average velocity in kilometers per hour

Westkost [7]

Answer:

96.5 km/h

Explanation:

The average velocity of the train is given by:

$v=\frac{d}{t}$

where

d is the displacement

t is the time taken

For this train, we have:

d = 55 km south (displacement is a vector, so we must also consider the direction)

$t= 34 min \cdot \frac{1}{60 min/h}=0.57 h$

Substituting into the equation, we find the average velocity:

$v=\frac{55 km}{0.57 h}=96.5 km/h$

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3 years ago

Select the correct statement about osmolarity. a) Osmolarity measures the moles of solute per liter of solution. b) The contents

8090 [49]

Answer:

a) Osmolarity measures the moles of solute per liter of solution.

Explanation:

Osmolarity is defined as the number of moles of solute that contribute to the osmotic pressure, per liter of solution, of solution. That is, the measurement of the solute concentration. The prefix "osmo-" indicates the possible variation of the osmotic pressure in the cells, which will occur when the solution is introduced into the body.

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4 years ago

The position of a charge in an electric field gives it _____electric

kykrilka [37]

Answer:

The space surrounding a charged object is affected by the presence of the charge; an electric field is established in that space. A charged object creates an electric field - an alteration of the space or field in the region that surrounds it. Other charges in that field would feel the unusual alteration of the space.

Explanation:

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3 years ago

In measuring the width of a hair sample, a light of wavelength 500 nm is used. The hair sample is 40 um in radius. With the scre

sergejj [24]

Answer:

The distance of the second dark band away from the central bright spot be located is $5.625\times10^{-2}\ m$

Explanation:

Given that,

Wave length = 500 nm

Radius $d= 40\ \mu m$

Distance from the hair sample D= 6 m

We need to calculate the distance of the second dark band away from the central bright spot be located

$\sin\theta=\dfrac{y}{D}$

$\sin\theta=\dfrac{y}{6}$

Using formula for dark fringe

$(n-\dfrac{1}{2})\lambda=2d\sin\theta$

Put the value into the formula

$(2-\dfrac{1}{2})\times500\times10^{-9}=2\times40\times10^{-6}\times\dfrac{y}{6}$

$y=\dfrac{(2-\dfrac{1}{2})\times500\times10^{-9}\times6}{2\times40\times10^{-6}}$

$y=0.05625\ m$

$y=5.625\times10^{-2}\ m$

Hence, The distance of the second dark band away from the central bright spot be located is $5.625\times10^{-2}\ m$

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3 years ago

An airplane is flying at a speed of 200 m/s in level flight at an altitude of 800 m. A package is to be dropped from the airplan

erik [133]

Answer:

The

Explanation:

The horizontal distance covered is known as the range expressed as;

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Hence the package should be released at a distance of 2555.54m

8 0

3 years ago