The total charge held in a battery is 0.
Answer:
Explanation:
Conservation of angular momentum
The MGR originally has momentum
L = 100(3.0) = 300 kg•m²/s²
The child can be thought of as a point mass with I = mr²
When she jumps onto the rim of the MGR
300 = (100 + 22(2.0²)ω
ω = 300 / 188 = 1.5957... 1.6 rad/s
As she moves toward the center of the MGR, her moment of inertia goes to zero as her radius goes to zero.
The angular velocity when she reaches the center will again be 3.0 rad/s
Answer:
At 3.86K
Explanation:
The following data are obtained from a straight line graph of C/T plotted against T2, where C is the measured heat capacity and T is the temperature:
gradient = 0.0469 mJ mol−1 K−4 vertical intercept = 0.7 mJ mol−1 K−2
Since the graph of C/T against T2 is a straight line, the are related by the straight line equation: C /T =γ+AT². Multiplying by T, we get C =γT +AT³ The electronic contribution is linear in T, so it would be given by the first term: Ce =γT. The lattice (phonon) contribution is proportional to T³, so it would be the second term: Cph =AT³. When they become equal, we can solve these 2 equations for T. This gives: T = √γ A .
We can find γ and A from the graph. Returning to the straight line equation C /T =γ+AT². we can see that γ would be the vertical intercept, and A would be the gradient. These 2 values are given. Substituting, we f ind: T =
√0.7/ 0.0469 = 3.86K.
Answer:
Walking burns up more energy,1740000J
Explanation:
Given that the displacement is 5.0km, and running at 10km/h and uses, walking at 3km/hr and uses 290watts:
Energy consumption for running is calculated as:
Energy consumption for walking is calculated as:
Walking is a slower process hence the need for more energy over longer periods raltive to running the same distance.
Hence walking burns more energy; 1,740,000J. It burns more because you walk for a greater period of time.
