Ask question

Ask question

All categories

3 years ago

7

A 300-kg truck moving rightward with a speed of 5 km/hr collides head on with a 1000kg car moving leftward with a speed of 100 k

m/hr. The two vehicles stick together and move with the same velocity after the collision determine the post - collision speed of the car and truck

1 answer:

igor_vitrenko [27]3 years ago

7 0

Answer:

The final velocity of the vehicles will be -75km per hour (leftwards).

Explanation:

Let us call $m_1$ , $v_1$ mass and velocity of the truck , $m_2, v_2$ mass and velocity of the car, and $v_f$ the final velocity of the vehicles.

The law of conservation of momentum states that

$m_1v_1-m_2v_2= v_f(m_1+m_2)$

solving for $v_f$ we get:

$v_f = \dfrac{m_1v_1-m_2v_2}{m_1+m_2}$

putting in numerical values

$m_1 =300 kg \\v_1 =5km/hr = 1.39m/s\\m_2 = 1000kg\\v_2 = 100km/hr = 27.78m/s$

$v_f = \dfrac{300*(1.39)-1000*(27.78)}{300+1000}$

$\boxed{v_f = -21.0m/s }$ (<em>the negative sign indicates that the vehicles are moving in the leftward direction)</em>

or -75.8 km per hour.<em> </em>

You might be interested in

Nerve cells transmit electric signals through their long tubular axons. These signals propagate due to a sudden rush of Na+ ions

iren [92.7K]

Answer:

$I = \frac{9.12x10^{-8} C}{0.007 s}= 1.30285 x10^{-5} \frac{C}{s}=1.30285 x10^{-5} A = 13.02 \mu A$

Explanation:

For this case we have the following info given:

Number of Na+ ions $5.7 x10^{11} ions$

Each ion have a charge of +e and the crage of the electron is $1.6 x10^{-19}C$

The time is given $t = 7 ms$ if we convert this into seconds we got:

$t = 7ms * \frac{1s}{1000 ms}= 0.007s$

Now we can use the following formula given from the current passing thourhg a meter of nerve axon given by:

$Q = Ne$

Where N represent the number of ions, e the charge of the electron and Q the total charge

If we replace on this case we have this:

$Q= 5.7x10^{11} * (1.6 x10^{-19}C) = 9.12x10^{-8} C$

And from the general definition of current we know that:

$I =\frac{Q}{t}$

And since we know the total charge Q and the time we can replace:

$I = \frac{9.12x10^{-8} C}{0.007 s}= 1.30285 x10^{-5} \frac{C}{s}=1.30285 x10^{-5} A = 13.02 \mu A$

The current during the inflow charge in the meter axon for this case is $13.02 \mu A$

3 0

3 years ago

What is true about energy that is added to a closed system?

Setler [38]

The correct answer is B

6 0

3 years ago

Read 2 more answers

Write<br>any<br>to increase<br>magnitude of current in dynamo

Svetach [21]

Answer:

Explanation:

It can be increased by: increasing the rate of rotation. Increasing the strength of the magnetic field. Increasing the number of turns on the coil.

Hope this helps

plz mark it as brainliest!!!!!!

4 0

2 years ago

Which of the following are for vector directione?

Inga [223]

Answer:
C. outside 45 degrees
Step-by-step explanation:
C. outside 45 degrees
because it can be any point or direction outside 45 degrees

8 0

2 years ago

Snorkelers breathe through tubes that extend above the surface of the water. In prin- ciple, a snorkeler could go deeper with a

Yanka [14]

Answer:

h = 1.02 m

Explanation:

This is a fluid mechanics exercise, where the pressure is given by

P = $P_{atm}$ + ρ g h

The gauge pressure is

P - $P_{atm}$ = ρ g h

In this case the upper part of the tube we have the atmospheric pressure. and the diver can exert a pressure 10 KPa below the outside pressure, this must be the gauge pressure

$P_{m}$ = P - $P_{atm}$

$P_{m}$ = ρ g h

h = $P_{m}$ / ρ g

calculate

h = 10 103 / (1000 9.8)

h = 1.02 m

This is the depth at which man can breathe

8 0

2 years ago