The mass of ice melted as a result of friction between the ice and the horizontal surface is 2.78g
<u>Explanation:</u>
Given,
Temperature, T = 0°C
Initial mass, Mi = 62kg
Speed, s = 5.48m/s
Distance, x = 26.8m
Friction is present.
Mass of ice melted = ?
We know,
The amount of energy required for the melting of ice is exactly equal to the initial kinetic energy of the block of ice
and

Therefore, 
KE = 930.94 Joules
Ice melting lateral heat is 334 kJ/kg = 334000 J/kg.
Therefore, the melted mass of the ice = 930.94 / 334000 = 0.00278 kg = 2.78 g.
Thus, The mass of ice melted as a result of friction between the ice and the horizontal surface is 2.78g
We can find the energy needed to ionize the hydrogen atom.
We can find the wavelength of a spectral line.
We can find the energy change of the electron moving between two levels.
The first atomic model to adequately explain the radiation spectra of atomic hydrogen was Bohr's model of the hydrogen atom. The atomic Hydrogen model was first presented by Niels Bohr in 1913. Rutherford's model of the hydrogen atom leaves several holes, which Bohr's model of the hydrogen atom tries to fill in.
It has a particular place in history since it introduced the quantum theory, which led to the development of quantum mechanics. Bohr proposed that electrons moved in predetermined orbits or shells with defined radii around the nucleus. It was impossible for electrons to reside between any shells other than those having a radius given by the equation below.


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Answer:
For instance, an object is moving and we can say that a force is acting or must have been acted upon to cause the state of motion. When force is applied, it changes the position of the object concerning time resulting in motion. The motion, in other words, is described as a change in speed or change in direction.
Kinetic energy is the energy of a moving object.
Kinetic energy can be calculated using the following equation;
K.E =

where - m - mass of object
v - speed of object
substituting the values in the equation
K.E = 1/2 x 21 kg x (1 m/s)²
K.E = 10.5 J