I believe the answer is 16
is the algebraic representation for an exponential function
Step-by-step explanation:
Given:
f(x + 1) = 4.f(x)
f(3) = 16
To Find:
Algebraic representation for an exponential function=?
Solution:
From the formula f(x+n) = 
f(x)
when n= 1, x= 3
f(3+1)= 4(1)f(3)
f(4)= 4f(3)
Substituting the value of f(3)
f(4)= 4f(3)
f(4)= 4 x 16
f(4)= 64
f(4)=
f (5) = x 16
f (5) = x
f(5)= 
Similarly,
F(6) = 
Hence,
Answer:
A
Step-by-step explanation:
Answer:
Step-by-step explanation:
We are looking for the value of x so that the function has the given value in the following:
1) h(x) = -7x; h(x)=63
From the function given above,
If h(x) = 63, then,
h(x) = 63 = -7x
-7x = 63
Dividing the left hand side and right hand side of the equation by -7, it becomes
-7x/-7 = 63/-7
x = - 9
2) m(x) = 4x + 15; m(x)=7
From the function given above,
If m(x) = 7, then,
m(x) = 7 = 4x + 15
7 = 4x + 15
4x = 15 - 7 = 8
Dividing the left hand side and right hand side of the equation by 4, it becomes
4x/4 = 8/4
x = 2
3) q(x) = 1/2x - 3; q(x) = -4
From the function given above,
If q(x) = - 4, then,
q(x) = - 4 = 1/(2x - 3) =
Cross multiplying,
-4(2x-3) = 1
-8x +12 = 1
Collecting like terms,
-8x = 1 - 12
-8x = -11
Dividing the left hand side and right hand side of the equation by -8, it becomes
-8x/8 = -11/-8
x = 11/8
