3 years ago

Plotting these two equations on a graph. p=6-2q p=4+q

1 answer:

7 0

Put into slope intercept form, y=mx+b where m=slope
p=-2q+6
slope is -2
subsitute values for q and get values for p
q=0, p=6
(q,p)
(0,6)
(1,4)

p=q+4
slope is 1
subsitutte
q=0,p=4
(q,p)
(0,4)
(1,5)

below are the graphs

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Write the first six multiples of the number 4:

8_murik_8 [283]

4,8,12,16,20,24
4x1=4
4x2=8
4x3=12
4x4=16
4x5=20
4x6=24

8 0

3 years ago

Read 2 more answers

I need some help with this one

k0ka [10]

I believe the answer is 3

8 0

3 years ago

How to solve this showing all work ! Also explain why they aren’t polynomials if you can :)

Lesechka [4]

Polynomials are linear combinations of positive integer powers. For example,

$x^{100}+30x^2-\sqrt 2\,x+21$

is a polynomial, but

$-x^{-1}-4x^\pi+x^{3/2}$

is not.

(In case you're unfamiliar with the term, a linear combination of two quantities is the sum of scaled versions of those quantities, e.g. a general linear combination of $a$ and $b$ is $k_1a+k_2b$ , where $k_1,k_2$ are any numbers.)