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antoniya [11.8K]
3 years ago
14

A commercial airplane travels 5,000 feet east and then ascends 3,000 feet from its starting point in the sky. Upon noticing a se

vere storm system on the horizon, the pilot decides to return to the starting point. A) how much distance does the plane have to travel to turn back? B) at what angle would the plane need to travel to return to its starting point. (1,000 feet = 1 unit)
Mathematics
1 answer:
svp [43]3 years ago
8 0

Answer:

A) 5830.95 B)59.04

Step-by-step explanation:

Solve for the hypotenuse of 5,000 and 3,000

Use tangent to find the angle

tanx = 5,000/3,000

x=59.04

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<u>Answer </u><u>:</u><u>-</u>

Given inequality ,

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From the options ,

<u>When </u><u>x </u><u>is </u><u>3</u><u> </u><u>and </u><u>y </u><u>=</u><u> </u><u>9</u>

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<u>When</u><u> </u><u>x </u><u>is </u><u>-</u><u>5</u><u> </u><u>y</u><u> </u><u>is </u><u>5</u><u> </u>

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<u>When </u><u>x </u><u>is </u><u>3</u><u> </u><u>y </u><u>is </u><u>-</u><u>6</u><u> </u>

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<u>When </u><u>x </u><u>is </u><u>-</u><u>2</u><u> </u><u>y </u><u>is </u><u>-</u><u>5</u><u> </u>

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<u>When </u><u>x </u><u>is </u><u>2</u><u> </u><u>y </u><u>is </u><u>8</u><u> </u>

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<u>When</u><u> </u><u>x </u><u>is </u><u>-</u><u>6</u><u> </u><u>y </u><u>is </u><u>0</u><u> </u>

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I’ve never done this before but..
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we translate y up 1 which would be 5.
so i’m thinking the answer would be (-4,5)
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