Answer:
the two lines observed correspond to Hydrogen and Helium
Explanation:
One of the great principles of atomic physics is that the emission and absorption lines of atoms are the same, in addition, each different element has a series of characteristic lines with which we can identify it.
Bohr's atomic model allows to fully explain the spectrum of lines and absorption of Hydrogen, in this case the line
λ = 656 nm
corresponds to a hydrogen trasition of the Balmer series from state n = 3 to state n = 2
The other line identified λ = 587 nm does not correspond to any hydrogen line and neither to heavy element lines, so this line when it was discovered was assigned to a new element, which was called Helium. This line is explained this element was assigned an atomic number (charge) of +2 and a mass of + 4 u, specifically it is a transition from level n = 3 to level n = 2
therefore the two lines observed correspond to Hydrogen and Helium
Answer:
The answer is "Option A".
Explanation:
In the given scenario, Two metal plates were produced in contrast to values separated by a small distance and three potential points for just a slight net charge are accessible. All three points would have the same electrical energy since the power generation is consistent from both sides as well as the position is placed at a slight net value so it has the highest electrical energy.
Answer:
n = 2.25 x 10¹⁴ electrons/s
Explanation:
The amount of electric current is defined as the electric charge passing through an area per unit time. Hence:
I = q/t
where,
I = Current
q = amount of charge
t = time interval
but,
q = ne
therefore,
I = ne/t
where,
n = no. of electrons
e = charge on single electron = 1.6 x 10⁻¹⁹ C
t = 1 s (for electrons passing per second)
I = Current = 36 μA = 3.6 x 10⁻⁵ A
Therefore,
3.6 x 10⁻⁵ A = n(1.6 x 10⁻¹⁹ C)/1 s
n = (3.6 x 10⁻⁵ A)/(1.6 x 10⁻¹⁹ C)
<u>n = 2.25 x 10¹⁴ electrons/s</u>
Answer:
91.5 m/s
Explanation:
m = mass of clay = 12 g = 0.012 kg
M = mass of wooden block = 100 g = 0.1 kg
d = distance traveled by the combination before coming to rest = 7.5 m
μ = Coefficient of friction = 0.65
V = speed of the combination of clay and lock just after collision
V' = final speed of the combination after coming to rest = 0 m/s
acceleration caused due to friction is given as
a = - μ g
a = - (0.65) (9.8)
a = - 6.37 m/s²
Using the kinematics equation
V'² = V² + 2 a d
0² = V² + 2(- 6.37) (7.5)
V = 9.8 m/s²
v = speed of clay just before collision
Using conservation of momentum
m v = (m + M) V
(0.012) v = (0.012 + 0.100) (9.8)
v = 91.5 m/s
Answer:
q = 2 10⁻⁸ C
Explanation:
For this exercise we use the translational equilibrium equation
F_e -A =
F_e = W
the electric force is given by Coulomb's law
F_e =
in this case they indicate that the loads on the tapes are equal
F_e = k q² / r²
we substitute
k q² / r² = m g
q =
calculate
q =
q =
q = 1,999 10⁻⁸ C
q = 2 10⁻⁸ C